Question

可能重复：
mysql_fetch_array() expects parameter 1 to be resource, boolean given in select

这是我的代码：

<html>
    <head>
    </head>

    <body>
        <?php 
            $user = mysql_real_escape_string($_GET["u"]);
            $pass = mysql_real_escape_string($_GET["p"]);

            $query = "SELECT * FROM usario WHERE username = '$user' AND password = '$pass'";

            mysql_connect(localhost, "root", "");
            @mysql_select_db("multas") or die( "Unable to select database");

            $result=mysql_query($query);
            if(mysql_numrows($result) > 0){
                echo 'si';
            }   
         ?>
    </body>
</html>

这是我尝试运行时遇到的错误

Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\useraccess.php on line 7

Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in C:\xampp\htdocs\useraccess.php on line 7

Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\useraccess.php on line 8

Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in C:\xampp\htdocs\useraccess.php on line 8

Warning: mysql_numrows() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\useraccess.php on line 16

Answer 1

您需要在致电

之前建立数据库连接

mysql_real_escape_string

如果您不想这样做，请使用

函数mysql_escape_string

相反，因为它不关心连接

Answer 2

你需要在'localhost'周围加上单引号：

mysql_connect('localhost', 'root', '');

另外，空白root密码？真的？

Answer 3

将mysql_connect(localhost, "root", "");移到$user = ...

之上

尝试访问我的数据库时拒绝访问

3 个答案: