我正在尝试编写Tic Tac Toe游戏，我不知道如何检查并查看是否有人赢了。我在这个网站上看到了一些答案，但这些答案似乎都不符合我的计划。任何帮助，将不胜感激！！！！
import turtle
t = turtle.Pen()
t.speed(300),t.pu(),t.goto(-150,-150),t.pd()
canvas = turtle.Screen()
canvas.setup(800,400)
canvas.title("Tic Tac Toe")
def square():
for i in range(0,4):
t.forward(100)
t.left(90)
def grid():
for i in range(0,3):
square()
t.forward(100)
grid(),t.pu(),t.goto(-150,-50),t.pd()
grid(),t.pu(),t.goto(-150,50),t.pd()
grid(),t.ht()
def Xs_and_Os(choice, seal):
t.pu()
grid_pos = {1:(-100,100), 2:(0,100), 3:(100,100),
4:(-100,0), 5:(0,0), 6:(100,0),
7:(-100,-100),8:(0,-100), 9:(100,-100)}
if choice in grid_pos:
t.setpos(grid_pos[choice])
t.pd()
t.write(seal, font = ("Arial",30,"bold"))
grid_choices = [1,2,3,4,5,6,7,8,9]
while grid_choices != []:
x = canvas.numinput( "Player 1, choose a grid."," ",9,1)
while x not in grid_choices:
x = canvas.numinput("Player 1, choose again."," ",9,1)
grid_choices.remove(x)
Xs_and_Os(x,"X")
y = canvas.numinput("\n" + "Player 2, choose a square. "," ",9,1)
while y not in grid_choices:
y = canvas.numinput("\n" + "Player 2, choose a square. "," ",9,1)
grid_choices.remove(y)
Xs_and_Os(y, "O")
答案 0 :(得分：1)
要检查某人是否赢了，你需要检查所有可能的胜利条件。在tic-tac-toe中，有8：3水平，3垂直和2对角线。您必须设置一些可以与
比较的值def check_for_win(entries, player):
# entries: list grid with X's and O's
# player: string - 'X' or 'O', whoever's turn it is
if entries[0] == entries[1] == entries[2] == player or \
entries[3] == entries[4] == entries[5] == player or \
entries[6] == entries[7] == entries[8] == player:
return True
elif entries[0] == entries[3] == entries[6] == player or \
entries[1] == entries[4] == entries[7] == player or \
entries[2] == entries[5] == entries[8] == player:
return True
elif entries[0] == entries[4] == entries[8] == player or \
entries[2] == entries[4] == entries[7] == player:
return True
return False
（在您提供的代码中）
....
if choice in grid_pos:
t.setpos(grid_pos[choice])
entries[choice-1] = seal # new
t.pd()
t.write(seal, font = ("Arial",30,"bold"))
if check_for_win(grid_pos, seal): # new
has_won(seal)
grid_choices = [1,2,3,4,5,6,7,8,9]
entries = 9*[0] # new
...
def has_won(player): # new
print("Congrats %s's, you have won!" % seal) # new
当然，就像所有事情一样，这是一种方法（这是我在进行c ++练习时设置我的井字游戏的方法）。我选择使用entries来比较当前的董事会。如果玩家1在单元格4中放置X，则entries[3] = 'X'。然后check_for_win下的if / elif语句只检查8个胜利条件中的一个。 entries[0] == entries[1] == entries[2] == player表示对entries中的第1，第2和第3个索引进行python检查，它们等于任何人。这样，您就不会在空白单元格上获胜！当然，如果没有获胜者，那么return False可以确保游戏进展顺利
干杯！ 马特
（评论是否需要更多解释或我输入错误信息）
答案 1 :(得分：1)
# checking for the winner of the tic tac toe game
def check_if_winner(self, tic_tac_toe):
human = 0
computer = 0
# row
for row in range(self.row):
count = 0
for col in range(self.column):
if tic_tac_toe[row][col] == "x" and tic_tac_toe[row][col] != " ":
count += 1
else:
pass
if count == self.column:
human += 1
return True
# column
for col in range(self.column):
count = 0
for row in range(self.row):
if tic_tac_toe[row][col] == "x" and tic_tac_toe[row][col] != " ":
count += 1
else:
pass
if count == self.column:
human += 1
return True
# diagonal
count = 0
for col in range(self.column):
# count = 0
for row in range(self.row):
if row == col and tic_tac_toe[row][col] != " ":
if tic_tac_toe[row][col] == "x":
count += 1
else:
pass
if count == self.column:
human += 1
return True
count = 0
sum = self.column
for row in range(self.row):
for col in range(self.column):
if (col + row) == (sum - 1) and tic_tac_toe[row][col] != " ":
if tic_tac_toe[row][col] == "x":
count += 1
else:
pass
if count == self.column:
human += 1
return True
# checking for the winner
if computer or human == 1 and self.total_chances < self.chance:
if human > computer:
print("human wins")
elif computer > human:
print("computer wins")
else:
print("match draw")
答案 2 :(得分：0)
这是我的方式:)还有更多的事情要做
from tkinter import *
from tkinter import ttk
import tkinter.messagebox
polje = []
igrac1 = []
igrac2 = []
i = 0
j = 0
pobjeda = {(1, 2, 3), (4, 5, 6), (7, 8, 9), (1, 5, 9), (3, 5, 7), (1, 4, 7), (3, 6, 9), (2, 5, 8)}
class App:
def __init__(self, master):
self.frame1 = Frame(master)
self.frame1.grid(row=0, columnspan=3)
self.L1 = Label(master, text="Igrac1")
self.L1.grid(row=0, column=0)
self.L2 = Label(master, text="Draw")
self.L2.grid(row=0, column=1)
self.L3 = Label(master, text="Igrac2")
self.L3.grid(row=0, column=2)
self.frame2 = Frame(master)
self.frame2.grid(row=1, columnspan=3)
self.L4 = Label(master, text="#") #broj pobjeda igraca1
self.L4.grid(row=1, column=0)
self.L5 = Label(master, text="#") # broj remija
self.L5.grid(row=1, column=1)
self.L6 = Label(master, text="#") # broj pobjeda igraca2
self.L6.grid(row=1, column=2)
self.frame3 = Frame(master)
self.frame3.grid(row=2, column=0)
self.c1 = Canvas(self.frame3, width=70, height=70)
self.c1.bind("<Button-1>", lambda event, args=self.c1: self.IspisX(event, args))
self.c1.grid(sticky=NW)
self.c1.create_line(70, 0, 70, 70)
self.frame4 = Frame(master)
self.frame4.grid(row=2, column=1)
self.c2 = Canvas(self.frame4, width=70, height=70)
self.c2.grid(sticky=NW)
self.c2.create_line(70, 0, 70, 70)
self.frame5 = Frame(master)
self.frame5.grid(row=2, column=2)
self.c3 = Canvas(self.frame5, width=70, height=70)
self.c3.grid(sticky=NW)
self.frame6 = Frame(master)
self.frame6.grid(row=3, column=0)
self.c4 = Canvas(self.frame6, width=70, height=70)
self.c4.grid(sticky=NW)
self.c4.create_line(1, 1, 69, 1)
self.c4.create_line(70, 0, 70, 70)
self.frame7 = Frame(master)
self.frame7.grid(row=3, column=1)
self.c5 = Canvas(self.frame7, width=70, height=70)
self.c5.grid(sticky=NW)
self.c5.create_line(1, 1, 69, 1)
self.c5.create_line(70, 0, 70, 70)
self.frame8 = Frame(master)
self.frame8.grid(row=3, column=2)
self.c6 = Canvas(self.frame8, width=70, height=70)
self.c6.grid(sticky=NW)
self.c6.create_line(1, 1, 69, 1)
self.frame9 = Frame(master)
self.frame9.grid(row=4, column=0)
self.c7 = Canvas(self.frame9, width=70, height=70)
self.c7.grid(sticky=NW)
self.c7.create_line(1, 1, 69, 1)
self.c7.create_line(70, 0, 70, 70)
self.frame10 = Frame(master)
self.frame10.grid(row=4, column=1)
self.c8 = Canvas(self.frame10, width=70, height=70)
self.c8.grid(sticky=NW)
self.c8.create_line(1, 1, 69, 1)
self.c8.create_line(70, 0, 70, 70)
self.frame11 = Frame(master)
self.frame11.grid(row=4, column=2)
self.c9 = Canvas(self.frame11, width=70, height=70)
self.c9.grid(sticky=NW)
self.c9.create_line(1, 1, 69, 1)
def IspisX(self, event, x):
if x == self.c1:
if 1 not in polje:
x.create_line(10, 10, 60, 60)
x.create_line(10, 60, 60, 10)
polje.append(1)
igrac1.append(1)
self.Igranje("igrac2")
else:
pass
elif x == self.c2:
if 2 not in polje:
x.create_line(10, 10, 60, 60)
x.create_line(10, 60, 60, 10)
polje.append(2)
igrac1.append(2)
self.Igranje("igrac2")
else:
pass
elif x == self.c3:
if 3 not in polje:
x.create_line(10, 10, 60, 60)
x.create_line(10, 60, 60, 10)
polje.append(3)
igrac1.append(3)
self.Igranje("igrac2")
else:
pass
elif x == self.c4:
if 4 not in polje:
x.create_line(10, 10, 60, 60)
x.create_line(10, 60, 60, 10)
polje.append(4)
igrac1.append(4)
self.Igranje("igrac2")
else:
pass
elif x == self.c5:
if 5 not in polje:
x.create_line(10, 10, 60, 60)
x.create_line(10, 60, 60, 10)
polje.append(5)
igrac1.append(5)
self.Igranje("igrac2")
else:
pass
elif x == self.c6:
if 6 not in polje:
x.create_line(10, 10, 60, 60)
x.create_line(10, 60, 60, 10)
polje.append(6)
igrac1.append(6)
self.Igranje("igrac2")
else:
pass
elif x == self.c7:
if 7 not in polje:
x.create_line(10, 10, 60, 60)
x.create_line(10, 60, 60, 10)
polje.append(7)
igrac1.append(7)
self.Igranje("igrac2")
else:
pass
elif x == self.c8:
if 8 not in polje:
x.create_line(10, 10, 60, 60)
x.create_line(10, 60, 60, 10)
polje.append(8)
igrac1.append(8)
self.Igranje("igrac2")
else:
pass
elif x == self.c9:
if 9 not in polje:
x.create_line(10, 10, 60, 60)
x.create_line(10, 60, 60, 10)
polje.append(9)
igrac1.append(9)
self.Igranje("igrac2")
else:
pass
def IspisO(self, event, x):
if x == self.c1:
if 1 not in polje:
x.create_oval(25, 25, 50, 50)
polje.append(1)
igrac2.append(1)
self.Igranje("igrac1")
else:
pass
elif x == self.c2:
if 2 not in polje:
x.create_oval(25, 25, 50, 50)
polje.append(2)
igrac2.append(2)
self.Igranje("igrac1")
else:
pass
elif x == self.c3:
if 3 not in polje:
x.create_oval(25, 25, 50, 50)
polje.append(3)
igrac2.append(3)
self.Igranje("igrac1")
else:
pass
elif x == self.c4:
if 4 not in polje:
x.create_oval(25, 25, 50, 50)
polje.append(4)
igrac2.append(4)
self.Igranje("igrac1")
else:
pass
elif x == self.c5:
if 5 not in polje:
x.create_oval(25, 25, 50, 50)
polje.append(5)
igrac2.append(5)
self.Igranje("igrac1")
else:
pass
elif x == self.c6:
if 6 not in polje:
x.create_oval(25, 25, 50, 50)
polje.append(6)
igrac2.append(6)
self.Igranje("igrac1")
else:
pass
elif x == self.c7:
if 7 not in polje:
x.create_oval(25, 25, 50, 50)
polje.append(7)
igrac2.append(7)
self.Igranje("igrac1")
else:
pass
elif x == self.c8:
if 8 not in polje:
x.create_oval(25, 25, 50, 50)
polje.append(8)
igrac2.append(8)
self.Igranje("igrac1")
else:
pass
elif x == self.c9:
if 9 not in polje:
x.create_oval(25, 25, 50, 50)
polje.append(9)
igrac2.append(9)
self.Igranje("igrac1")
else:
pass
def Igranje(self, turn):
Game = True
i = 0
j = 0
while Game:
for k in pobjeda:
x = set(k)
if x.issubset(set(igrac1)):
tkinter.messagebox.showinfo("Izvjestaj", "Pobjedio je igrac 1")
elif x.issubset(set(igrac2)):
tkinter.messagebox.showinfo("Izvjestaj", "Pobjedio je igrac 2")
elif(len(polje)==9):
tkinter.messagebox.showinfo("Izvjestaj", "Partija je zavrsila remijem")
polje.append(10)
Game = False
break
else:
pass
if(turn == "igrac1"):
self.c1.bind("<Button-1>", lambda event, args=self.c1: self.IspisX(event, args)) #lambda funkcija je primila dva argumenta event i arg ,a njena zadaca je bila pozvati funckiju ispisX i poslati joj ta dva argumenta
self.c2.bind("<Button-1>", lambda event, args=self.c2: self.IspisX(event, args))
self.c3.bind("<Button-1>", lambda event, args=self.c3: self.IspisX(event, args))
self.c4.bind("<Button-1>", lambda event, args=self.c4: self.IspisX(event, args))
self.c5.bind("<Button-1>", lambda event, args=self.c5: self.IspisX(event, args))
self.c6.bind("<Button-1>", lambda event, args=self.c6: self.IspisX(event, args))
self.c7.bind("<Button-1>", lambda event, args=self.c7: self.IspisX(event, args))
self.c8.bind("<Button-1>", lambda event, args=self.c8: self.IspisX(event, args))
self.c9.bind("<Button-1>", lambda event, args=self.c9: self.IspisX(event, args))
turn = "igrac2"
i = i+1
print(i)
print("i")
break
else:
self.c1.bind("<Button-1>", lambda event, args=self.c1: self.IspisO(event, args))
self.c2.bind("<Button-1>", lambda event, args=self.c2: self.IspisO(event, args))
self.c3.bind("<Button-1>", lambda event, args=self.c3: self.IspisO(event, args))
self.c4.bind("<Button-1>", lambda event, args=self.c4: self.IspisO(event, args))
self.c5.bind("<Button-1>", lambda event, args=self.c5: self.IspisO(event, args))
self.c6.bind("<Button-1>", lambda event, args=self.c6: self.IspisO(event, args))
self.c7.bind("<Button-1>", lambda event, args=self.c7: self.IspisO(event, args))
self.c8.bind("<Button-1>", lambda event, args=self.c8: self.IspisO(event, args))
self.c9.bind("<Button-1>", lambda event, args=self.c9: self.IspisO(event, args))
j = j+1
print(j)
print("j")
turn = "igrac1"
break
if len(polje) < 10:
pass
else:
if(len(polje)==9):
tkinter.messagebox.showinfo("Izvjestaj", "Partija je zavrsila remijem")
Game = False
root = Tk()
a = App(root)
a.Igranje("igrac1")
root.mainloop()
答案 3 :(得分：0)
您可以尝试以下操作： 在下面找到端到端互动井字棋盘游戏的python代码。 代码看起来很冗长，可以优化，但它可以完美地用作交互式井字棋盘游戏。
#Function code to clear the output space (screen)
from IPython.display import clear_output
#code to display just board-
def ttt_borad(board):
cl = clear_output()
print('Your Tic-Tac-Toe board now:\n')
print(board[1] + "|" + board[2] + "|" + board[3])
print("________")
print(board[4] + "|" + board[5] + "|" + board[6])
print("________")
print(board[7] + "|" + board[8] + "|" + board[9])
#function code to accept player key choices-
def player_key():
player_choice = ''
play1 = ''
play2 = ''
while player_choice not in ('Y', 'N'):
player_choice = input("Player-1 would like to go first ? Enter Y/N: ")
player_choice = player_choice.upper()
if player_choice not in ('Y', 'N'):
print("Invalid Key")
else:
pass
if player_choice == 'Y':
while play1 not in ('X', 'O'):
play1 = input("Select your Key for Player-1 X or O: ")
play1 = play1.upper()
if play1 not in ('X', 'O'):
print("Invalid Key")
else:
pass
else:
while play2 not in ('X', 'O'):
play2 = input("Select your Key for Player-2 X or O: ")
play2 = play2.upper()
if play2 not in ('X', 'O'):
print("Invalid Key")
else:
pass
if play1 == 'X':
play2 = 'O'
elif play1 == 'O':
play2 = 'X'
elif play2 == 'X':
play1 = 'O'
elif play2 == 'O':
play1 = 'X'
print(f'Key for Player-1 is: {play1} and Key for Player-2 is: {play2}')
return play1, play2
#function code to accept key strokes to play game
def enter_key(key, bp):
play1, play2 = key
ind = ['1', '2', '3', '4', '5', '6', '7', '8', '9']
i = 1
while i < 10:
j = 0
k = 0
print(f'Game Move: {i}')
while j not in ind:
j = input("Player-1: Select position (1-9) for your Move: ")
if j not in ind:
print("Invalid Key or Position already marked")
else:
pass
x = ind.index(j)
ind.pop(x)
j = int(j)
bp[j] = play1
ttt_borad(bp)
i = i + 1
tf = game_winner(key, bp)
if tf == 1:
print("The Winner is: Player-1 !!")
break
print(f'Game Move: {i}')
if i == 10:
break
while k not in ind:
k = input("Player-2: Select position (1-9) for your Move: ")
if k not in ind:
print("Invalid Key or Position already marked")
else:
pass
y = ind.index(k)
ind.pop(y)
k = int(k)
bp[k] = play2
ttt_borad(bp)
i = i + 1
ft = game_winner(key, bp)
if ft == 2:
print("The Winner is: Player-2 !!")
break
return bp
#function code to calculate and display winner of the game-
def game_winner(key, game):
p1, p2 = key
p = 0
if game[1] == game[2] == game[3] == p1:
p = 1
return p
elif game[1] == game[4] == game[7] == p1:
p = 1
return p
elif game[1] == game[5] == game[9] == p1:
p = 1
return p
elif game[2] == game[5] == game[8] == p1:
p = 1
return p
elif game[3] == game[6] == game[9] == p1:
p = 1
return p
elif game[4] == game[5] == game[6] == p1:
p = 1
return p
elif game[3] == game[5] == game[7] == p1:
p = 1
return p
elif game[1] == game[2] == game[3] == p2:
p = 2
return p
elif game[1] == game[4] == game[7] == p2:
p = 2
return p
elif game[1] == game[5] == game[9] == p2:
p = 2
return p
elif game[2] == game[5] == game[8] == p2:
p = 2
return p
elif game[3] == game[6] == game[9] == p2:
p = 2
return p
elif game[4] == game[5] == game[6] == p2:
p = 2
return p
elif game[3] == game[5] == game[7] == p2:
p = 2
return p
else:
p = 3
return p
#Function code to call all functions in order to start and play game-
def game_play():
clear_output()
entry = ['M', '1', '2', '3', '4', '5', '6', '7', '8', '9']
ttt_borad(entry)
plk = player_key()
new_board = enter_key(plk, entry)
tie = game_winner(plk, new_board)
if tie == 3:
print("Game Tie !!! :-( ")
#code to continue game (Play game again)
print('Would you like to play again? ')
pa = input("Enter Y to continue OR Enter any other key to exit game: ")
pa = pa.upper()
if pa == 'Y':
game_play()
else:
pass
game_play()
＃在任何Python3编辑器中尝试整个代码，并让我知道您的反馈。 我已附上示例板代码显示方式。Sample Tic-Tac-Toe board by code
谢谢
答案 4 :(得分：-1)
将单元格条目转换为整数（例如，'O'为1，'X'为-1，空'为0），然后您可以检查8行中每一行的总和。
请参阅以下代码：
def convertToInteger(c):
if c.upper()=='X':
return -1
elif c.upper()=='O':
return 1
else:
return 0
lines = [[0, 1, 2],[3, 4, 5],[6, 7, 8],[0, 3, 6],[1, 4, 7],[2, 5, 8],[0, 4, 8],[2, 4, 6]]
entries =list('x xo xoxo')
entryValues=[convertToInteger(c) for c in entries]
lineValues =[sum(entryValue) for line in lines for entryValue in [[entryValues[j] for j in line]]]
if max(lineValues) == 3:
print("******** [o] wins!! ********")
elif min(lineValues) == -3:
print("******** [x] wins!! ********")