如何更改集合项的值

时间:2015-04-09 14:44:45

标签: vba excel-vba collections excel

使用此代码(在excel-vba中)我根据数组向集合中添加了许多项目 我使用数组的值作为键和字符串" NULL"作为每个项目的值。

Dim Coll As New collection
Dim myArr()

Set Coll = New collection
myArr() = Array("String1", "String2", "String3")

For i = LBound(myArr) To UBound(myArr)
    Coll.Add "NULL", myArr(i)
Next i

现在,如果我想更改项目的值,通过键识别它,我必须删除该项目然后添加具有相同键的项目,或者是否可以更改项目值?

以下是唯一的方法吗?

Coll.Remove "String1"
Coll.Add "myString", "String1"

或者是否有类似的东西:(我知道它不起作用)

Coll("String1") = "myString"

4 个答案:

答案 0 :(得分:5)

您还可以编写(公共)函数来更新集合。

public function updateCollectionWithStringValue(coll ax Collection, key as string, value as string) as collection
coll.remove key
coll.add value, key
set updateCollectionWithStringValue = coll
end function

您可以通过以下方式调用此功能:

set coll = updateCollectionWithStringValue(coll, "String1","myString")

然后你有一个班轮来调用。

答案 1 :(得分:0)

您不能使用Before参数来满足此要求吗?

示例:

Sub TestProject()
    Dim myStrings As New Collection
    Set myStringsRef = myStrings

    myStrings.Add item:="Text 1"
    myStrings.Add item:="Text 2"
    myStrings.Add item:="Text 3"

    ' Print out the content of collection "myStrings"
    Debug.Print "--- Initial collection content ---"
    PrintCollectionContent (myStringsRef)
    Debug.Print "--- End Initial collection content ---"

    ' Now we want to change "Text 2" into "New Text"
    myStrings.Add item:="New Text", Before:=2 ' myStrings will now contain 4 items
    Debug.Print "--- Collection content after adding the new content ---"
    ' Print out the 'in-between' status of collection "myStrings" where we have
    ' both the new string and the string to be replaced still in.
    PrintCollectionContent (myStringsRef)
    Debug.Print "--- End Collection content after adding the new content ---"

    myStrings.Remove 3
    ' Print out the final status of collection "myStrings" where the obsolete 
    ' item is removed
    Debug.Print "--- Collection content after removal of the old content ---"
    PrintCollectionContent (myStringsRef)
    Debug.Print "--- End Collection content after removal of the old content ---"

End Sub

Private Sub PrintCollectionContent(ByVal myColl As Variant)
    For i = 1 To myColl.Count()
        Debug.Print myColl.item(i)
    Next i
End Sub

这不是做这份工作吗?

答案 2 :(得分:0)

只需循环集合并将新值添加到新集合中...

function prep_new_collection(my_old_data as collection) as collection

dim col_data_prep as new collection

for i = 1 to my_old_data.count

if my_old_data(i)(0)= "whatever" then

  col_data_prep.add array("NULL", my_old_data(i)(1))

else

 col_data_prep.add array(my_old_data(i)(0), my_old_data(i)(1))

end if

next i

 set prep_new_collection = col_data_prep

end function

答案 3 :(得分:0)

我刚刚遇到了同样的问题,我想在这里发布我的解决方案,供任何可能需要它的人使用。我的解决方案是创建一个名为 EnhancedCollection 具有更新功能。将此代码保存到名为 EnhancedCollection.cls 的文件中,然后导入到您的项目中。

    VERSION 1.0 CLASS
    BEGIN
      MultiUse = -1  'True
    END
    Attribute VB_Name = "EnhancedCollection"
    Attribute VB_GlobalNameSpace = False
    Attribute VB_Creatable = False
    Attribute VB_PredeclaredId = False
    Attribute VB_Exposed = False
    Option Explicit
    
    Private data As New Collection
       
    '=================================ADD
    
    If IsMissing(key) Then
        If IsMissing(before) Then
            If IsMissing(after) Then
                data.Add Value
            Else
                data.Add Value, , , after
            End If
        Else
            data.Add Value, , before
        End If
    ElseIf key = "TEMP_ITEM" Then
        Exit Sub
    Else
        If IsMissing(before) Then
            If IsMissing(after) Then
                data.Add Value, key
            Else
                data.Add Value, key, , after
            End If
        Else
            data.Add Value, key, before
        End If
    End If
End Sub
'=================================REMOVE

Sub Remove(key As Variant)
    data.Remove key
End Sub

    '=================================COUNT
    
    Function Count() As Integer
        Count = data.Count
    End Function
    '=================================ITEM
    
    Function Item(key As Variant) As Variant
    'This is the default Function of the class
    Attribute Item.VB_Description = "returns the item"
    Attribute Item.VB_UserMemId = 0
    On Error GoTo OnError
        If VarType(key) = vbString Or VarType(key) = vbInteger Then
            Item = data.Item(key)
        End If
        Exit Function
    OnError:
        Item = Null
    End Function
    '=================================Update
    
    Function Update(key As Variant, Value As Variant) As Variant
    On Error GoTo OnError
        If VarType(key) = vbString Or VarType(key) = vbInteger Then
            data.Add "", "TEMP_ITEM", , key
            data.Remove key
            data.Add Value, key, "TEMP_ITEM"
            data.Remove "TEMP_ITEM"
        End If
        Exit Function
    OnError:
        Update = Null
    End Function

另外一个好处是,您可以随时添加更多功能。

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