大家好,我已经被困在这两天了。我正在使用Visual Studio 2013
并制作了一个Windows窗体项目。然后使用以下代码我试图插入值,但是"显示表数据" option生成一个包含空值的表。我做错了什么?
SqlConnection conn = new SqlConnection(System.Configuration.ConfigurationManager.
ConnectionStrings["WindowsFormsApplicationtodatabase.Properties.Settings.DatabasewebConnectionString"].ConnectionString);
conn.Open();
using (conn)
{
SqlCommand cmd = new SqlCommand("INSERT INTO webtable (Id, url_name) VALUES (@id, @url)");
cmd.CommandType = CommandType.Text;
cmd.Connection = conn;
cmd.Parameters.AddWithValue("@url", "nagia");
cmd.Parameters.AddWithValue("@id", "9");
cmd.ExecuteNonQuery();
}
答案 0 :(得分:1)
你可以试试这个
conn.Open();
string strQuery = "INSERT INTO webtable (Id, url_name) VALUES (@id, @url)";
SqlCommand cmd = new SqlCommand(strQuery, conn);
cmd.Parameters.AddWithValue("@url", "nagia");
cmd.Parameters.AddWithValue("@id", "9");
cmd.Connection = conn;
cmd.ExecuteNonQuery();
conn.Close();
答案 1 :(得分:0)
答案 2 :(得分:0)
您可以尝试此代码..
using (SqlConnection conn = new SqlConnection(System.Configuration.ConfigurationManager.ConnectionStrings["WindowsFormsApplicationtodatabase.Properties.Settings.DatabasewebConnectionString"].ConnectionString));
{
SqlCommand cmd = new SqlCommand("INSERT INTO webtable (Id, url_name) VALUES (@id, @url)",conn);
cmd.Parameters.AddWithValue("@url", "nagia");
cmd.Parameters.AddWithValue("@id", "9");
cmd.Connection = conn;
conn.Open();
cmd.ExecuteNonQuery();
conn.Close();
}