Question

我想在浏览器中打开/显示文件内容，但我不会工作。这是我的代码：

 @WebServlet("/Download")
public class Download extends HttpServlet {
private static final long serialVersionUID = 1L;

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {


    ByteArrayOutputStream baos = new ByteArrayOutputStream();
    String name = request.getParameter("id");
    String sep = File.separator;
    File file = new File("C:" + sep + "FILE" + sep + name);

    if(!file.exists())
    {
        response.getWriter().print("File not found");
        return;
    }


    InputStream in = new FileInputStream(file);
    byte[] buffer = new byte[4096];
    int i = 0;
    while((i = in.read(buffer)) != -1)
    { 
        baos.write(buffer, 0, i);

    }


     response.setContentType("application/pdf");
     response.setContentLength(baos.size());
     response.setHeader("Content-Disposition", "inline; filename=help.pdf");
     response.setHeader("Cache-Control", "cache, must-revalidate");
     response.setHeader("Pragma", "public");

    BufferedOutputStream bos = new BufferedOutputStream(response.getOutputStream());

    in.close();

    baos.writeTo(bos);
    baos.flush();
    bos.flush(); 
    bos.close();


  }

}

我尝试用servlet类打开该文件。我浏览器调试器，我可以看到响应正在进入，通常采用这种格式（JVBERi0xLjMNMSAwIG9iag08PC9UeXBl ...）。

感谢您的帮助

修改

在jsp站点上我用一个AJAX调用调用servlet，看起来像'id'是用户想要打开的fileName。

function downloadFile(id) {

$.ajax({
    url:"Download",
    type:"POST",
    data:"id="+id       
});

}

Answer 1

我认为您应该在ajax函数的downloadFile(id)调用中添加此代码。

success:function(response){
            $("#<Some_SPAN_OR_TextAreaID>").show();               
            $("#<Some_SPAN_OR_TextAreaID").html(response.responseText);
        }

显示文件的内容

1 个答案: