在SQL中选择set中的顶级项

时间:2015-04-12 20:51:27

标签: mysql sql sql-order-by

我有一张表,其中包含对象的位置,名称和价格。例如

Location | Name | Price
Store 1    Apple   $.50
Store 1    Pear    $.75
Store 2    Peach   $.75
Store 3    Mango   $1.50
Store 3    Melon   $2.00

我想要的是

Location | Name | Price
Store 1    Apple   $.50
Store 2    Peach   $.75
Store 3    Mango   $1.50

我该怎么做?

2 个答案:

答案 0 :(得分:1)

groub by中使用row_subquery

select location,name,price
from table_name
where (location,price) in
( select t.location,min(t.price)
  from table_name t
  group by t.location
)

您还可以使用self join

select t1.location,t1.name,t1.price
from table_name t1 
join
( select location,min(price) as price
  from table_name 
  group by location
) t2 on t1.location=t2.location and t1.price=t2.price

答案 1 :(得分:0)

使用以下sql查询。

Declare @table1 table(
Location varchar(256),
Name varchar(256),
Price varchar(256)
)

insert into @table1
select 'Store 1','Apple','$.50'
union select 'Store 1','Pear','$.75'
union select 'Store 2','Peach','$.75'
union select 'Store 3','Mango','$1.50'
union select 'Store 3','Melon','$2.00'

select * from @table1

select Location,Min(Name) as Name,Min(Price) as Price from 
@table1
group by Location
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