php:确定调用函数的位置

时间:2010-06-02 19:09:35

标签: php function-calls

有没有办法找出PHP中的函数从何处调用? 例如:

function epic()
{
  fail();
}

function fail()
{
  //at this point, how do i know, that epic() has called this function?
}

8 个答案:

答案 0 :(得分:122)

您可以使用debug_backtrace()

示例:

<?php

function epic( $a, $b )
{
    fail( $a . ' ' . $b );
}

function fail( $string )
{
    $backtrace = debug_backtrace();

    print_r( $backtrace );
}

epic( 'Hello', 'World' );

<强>输出:

Array
(
    [0] => Array
        (
            [file] => /Users/romac/Desktop/test.php
            [line] => 5
            [function] => fail
            [args] => Array
                (
                    [0] => Hello World
                )

        )

    [1] => Array
        (
            [file] => /Users/romac/Desktop/test.php
            [line] => 15
            [function] => epic
            [args] => Array
                (
                    [0] => Hello
                    [1] => World
                )

        )

)

答案 1 :(得分:24)

使用debug_backtrace()

function fail()
{
    $backtrace = debug_backtrace();

    // Here, $backtrace[0] points to fail(), so we'll look in $backtrace[1] instead
    if (isset($backtrace[1]['function']) && $backtrace[1]['function'] == 'epic')
    {
        // Called by epic()...
    }
}

答案 2 :(得分:16)

我找到的最快最简单的解决方案

usesOperand()

我在联想笔记本电脑上测试速度:英特尔Pentiom CPU N3530 2.16GHz,内存8GB

public function func() { //function whose call file you want to find
    $trace = debug_backtrace(DEBUG_BACKTRACE_IGNORE_ARGS, 1);
}

$trace: Array
(
    [0] => Array
        (
            [file] => C:\wamp\www\index.php
            [line] => 56
            [function] => func
            [class] => (func Class namespace)
            [type] => ->
        )

)

结果:

global $times;
$start = microtime(true);
$trace = debug_backtrace(DEBUG_BACKTRACE_IGNORE_ARGS, 1);
$times[] = microtime(true) - $start;

答案 3 :(得分:14)

所以,如果你仍然真的不知道如何,那么解决方案就是:

$backtrace = debug_backtrace();
echo 'Mu name is '.$backtrace[1]['function'].', and I have called him! Muahahah!';

答案 4 :(得分:5)

答案 5 :(得分:3)

尝试以下代码。

foreach(debug_backtrace() as $t) {              
   echo $t['file'] . ' line ' . $t['line'] . ' calls ' . $t['function'] . "()<br/>";
}

答案 6 :(得分:3)

如果要在堆栈顶部跟踪调用的确切来源,可以使用以下代码:

$call_origin = end(debug_backtrace(DEBUG_BACKTRACE_IGNORE_ARGS));

这将忽略链接函数并仅获取最相关的调用信息(相关内容松散使用,因为它取决于您要完成的操作)。

答案 7 :(得分:-1)

function findFunction($function, $inputDirectory=""){
    //version 0.1
    $docRoot = getenv("DOCUMENT_ROOT");
    $folderArray = null;
    $dirArray = null;

    // open directory
    $directory = opendir($docRoot.$inputDirectory);

    // get each entry
    while($entryName = readdir($directory)) {
        if(is_dir($entryName) && $entryName != "." && $entryName != ".."){
            $folderArray[] = str_replace($inputDirectory, "", $entryName);
        }
        $ext = explode(".", $entryName);
        if(!empty($ext[1])){
            $dirArray[] = $docRoot.$inputDirectory."/".$entryName;
        }
    }

    // close directory
    closedir($directory);
    $found = false;

    if(is_array($dirArray)){
        foreach($dirArray as $current){
            $myFile = file_get_contents($current);
            $myFile = str_replace("<?php", "", $myFile);
            $myFile = str_replace("?>", "", $myFile);
            if(preg_match("/function ".$function."/", $myFile)){
                $found = true;
                $foundLocation = $current;
                break;
            }
        }
    }
    if($found){
        echo $foundLocation;
        exit;
    } else if(is_array($folderArray)){
        foreach($folderArray as $folder){
            if(!isset($return)){
                $return = findFunction($function, $inputDirectory."/".$folder);
            } else if($return == false){
                $return = findFunction($function, $inputDirectory."/".$folder);
            }
        }
    } else {
        return false;
    }
}

findFunction("testFunction", "rootDirectory");

希望它有所帮助。如果实际函数在httpdocs之外,则无法找到它,因为服务器将被设置为不允许它。只测试了一个文件夹,但递归方法应该在理论上有用。

这就像0.1版本,但我不打算继续开发它,所以如果有人更新它可以随意重新发布它。