无法将表单字段输入数据库?

时间:2015-04-14 06:47:01

标签: php forms

我目前遇到问题,将表单字段推送到数据库中。这是我的HTML代码:

<form action=""  method="post">
<p>Gender:</p><input type="radio" value="Male" name="gender">Male</input>
<input type="radio" value="Female" name="gender">Female</input><br>
<p>Birthday :</p>
<input type="text" placeholder="Help VITians to wish you."></input><br>
<p>Relationship :</p>
<select name="relation">
<option value="I don't want to say">I dont want to say</option>
<option value="Single">Single</option>
<option value="In a Relationship">In a Relationship</option>
</select><br><br>
<input type="submit" name="basic" value="Submit"></input>
</form>

这是我的PHP代码:

<?php
  $senddata = @$_POST['basic'];

  //Password variables
  $gender = strip_tags(@$_POST['gender']);
  $birthday = strip_tags(@$_POST['birthday']);
  $relation = strip_tags(@$_POST['relation']);

  if ($senddata) {
  //If the form has been submitted ..
        //Check whether old password equals $db_password
            if (strlen($birthday) <= 4) {
             echo "Sorry! Birthday is not right! Try entering it in DD/MM/YYYY format.";
            }
            else if(empty($birthday)){
            echo "Please enter your Birthday";
            }
            else
            {
           $update_query = mysqli_query($conn,"UPDATE users SET gender='$gender', birthday='$birthday',relation='$relation' WHERE username='$user'");
           echo "Success! Your basic information has been updated!";

            }
         }
         else
         {
         }
?>

,但我无法进入数据库,我的PHP代码也没有在同一页面上显示错误消息。有什么错误吗?

2 个答案:

答案 0 :(得分:0)

首先在生日输入中给出名称设置数据库连接(如果没有设置),我在代码中的任何地方都看不到$user。请先检查$user是否有任何值或不是这样的:

$update = mysqli_query($conn,"UPDATE `users` SET `gender`='".$gender."', `birthday`='".$birthday."',`relation`='".$relation."' WHERE `username`='".$user."'");

答案 1 :(得分:0)

你的where条件和mysql连接也有问题。

请声明$ user和$ conn。

$user = "usernameindb";

//DATA BASE CONNECTION

$servername = "localhost";

$username = "username";

$password = "password";

$dbname = "myDB";

$conn = mysqli_connect($servername, $username, $password, $dbname);

$update_query = mysqli_query($conn,"UPDATE `users` SET `gender`='".$gender."', `birthday`='".$birthday."',`relation`='".$relation."' WHERE `username`='".$user."'");