Question

我正在尝试使用数组（＆＃39; selectedWorkshops＆＃39;），并将其中的对象移至注册的工作室＆＃39;。然后，我还要从所选的工作坊＆＃39;中删除这些对象。另一个阵列简称为“工作坊”。

请在此处查看我的codepen：http://codepen.io/trueScript/pen/wBVqNN

阵列：

var workshops = [
  {
    name: 'apples',
    WorkshopId: '19'
  },
  {
    name: 'oranges',
    WorkshopId: '3b'
  },
  {
    name: 'pears',
    WorkshopId: 'x6'
  },
  {
    name: 'pineapples',
    WorkshopId: '55'
  },
  {
    name: 'watermelons',
    WorkshopId: '8v'
  }
];

var selectedWorkshops = [
  {
    name: 'oranges',
    WorkshopId: '3b'
  },
  {
    name: 'watermelons',
    WorkshopId: '8v'
  },
  {
    name: 'pears',
    WorkshopId: 'x6'
  }
];

var registeredWorkshops = [];

应该将研讨会转移到注册工作坊＆＃39;并从选定的工作坊＆＃39;中删除它们和＆＃39;研讨会＆＃39;：

flipWorkshops = function(){
    var numberOfWorkshops = selectedWorkshops.length;
    var X = 1;
    for(var i = 0; i < numberOfWorkshops; i++ ){
        registeredWorkshops.push(selectedWorkshops[i]);
        for(var j = 0, arrayLength = workshops.length; j < arrayLength; j++) {
            var selectedWorkshop = selectedWorkshops[i];
            var originalWorkshop = workshops[j];
            if(selectedWorkshop == originalWorkshop){
                var matchingWorkshop = j;
                workshops = workshops.splice(j, 1);
                selectedWorkshops = selectedWorkshops.splice(i, 1);
            }
        }
    }
};
flipWorkshops();

为什么没有将对象正确地拼接出＆＃39;工作室＆＃39;和＆＃39;选择的工作坊＆＃39;像他们应该的阵列？我做错了什么？

Answer 1

“splice（）方法在数组中添加/删除项目，并返回删除的项目。” http://w3schools.com/jsref/jsref_splice.asp因此，基本上，您正在将研讨会简化为单个对象，即已删除的数组元素。

相反，改变：

workshops = workshops.splice(j, 1);
selectedWorkshops = selectedWorkshops.splice(i, 1);

...为：

workshops.splice(j, 1);
selectedWorkshops.splice(i, 1);

JSFiddle

也许这就是你想要的：

var registeredWorkshops = [];
var flipWorkshops = function(){
    var numberOfWorkshops = selectedWorkshops.length;
    var X = 1;
    for(var i = numberOfWorkshops - 1; i >= 0; i-- ){
        registeredWorkshops.push(selectedWorkshops[i]);
        var selectedWorkshop = selectedWorkshops[i];
        for(var j = workshops.length - 1; j >= 0; j--) {
            var originalWorkshop = workshops[j];
            if(selectedWorkshop.name == originalWorkshop.name &&
              selectedWorkshop.WorkshopId == originalWorkshop.WorkshopId){
                var matchingWorkshop = j;
                workshops.splice(j, 1);
                selectedWorkshops.splice(i, 1);
            }
        }
    }
};
flipWorkshops();

修正splice，按照jwatts1980的建议颠倒循环，将selectedWorkshop var移出循环，并比较每个对象项，而不是比较对象，因为{ {3}}

objects don't compare

JSFiddle Tweaked

基于For循环迭代的拼接阵列

1 个答案: