Question

我试图使用jQuery从我的JSON对象中检索错误message。我该怎么做呢？谢谢！

我的JSON看起来像这样：

{  
   "error":{  
      "errors":[  
         {  
            "domain":"global",
            "reason":"invalidParameter",
            "message":"Invalid value 'asdfcom.com'. Values must match the following regular expression: 'http(s)?://.*'",
            "locationType":"parameter",
            "location":"url"
         }
      ],
      "code":400,
      "message":"Invalid value 'asdfcom.com'. Values must match the following regular expression: 'http(s)?://.*'"
   }
}

我的Javascript看起来像这样：

error: function(xhr, status, error) {
    $("#mobileResults").css("color", "red");
    $("#mobileResults").text(xhr.responseText);
    console.log(xhr.responseText)
    $('.fa-spinner').hide();
}

Answer 1

很简单：

var jsonObj = JSON.parse(xhr.responseText); //your object;
var message = jsonObj.error.errors[0].message; //  Values must match the following regular expression:
var outsideMes = jsonObj.error.message; // Values must match the following regular expression:

您可以尝试使用此代码段，它可以正常运行

＆＃13;

var obj = {
  "error": {
    "errors": [{
      "domain": "global",
      "reason": "invalidParameter",
      "message": "Invalid value 'asdfcom.com'. Values must match the following regular expression: 'http(s)?://.*'",
      "locationType": "parameter",
      "location": "url"
    }],
    "code": 400,
    "message": "Invalid value 'asdfcom.com'. Values must match the following regular expression: 'http(s)?://.*'"
  }
}

console.log(obj.error.errors[0].message);
console.log(obj.error.message);

＆＃13;

Answer 2

尝试使用jQuery.parseJSON方法。

var jsonObj = jQuery.parseJSON(xhr.responseText); 
console.log(jsonObj.message);

试图从我的JSON对象中获取特定值

2 个答案: