SQL排名和顺序

时间:2015-04-15 14:19:09

标签: sql hive hql

我正在处理一个数据集,其中我希望为每个使用驱动程序SKU销售的class_rk获得#1卖家,然后在每个class_rk中使用#2卖家等.Class_rk(其中已与先前查询中已识别的sold_sku相关联。这是数据集:

 driver_sku sold_sku    class_rk    sold_units
 555        432           1         20
 555        235           2         17
 555        322           2         15
 555        253           1         14
 555        152           3         13
 555        732           1          9
 555        913           3          6

我正在寻找的输出:

 driver_sku sold_sku    class_rk    sold_units
 555        432           1         20
 555        235           2         17
 555        152           3         13
 555        253           1         14
 555        322           2         15
 555        913           3          6
 555        732           1          9

以下是我迄今为止尝试过的代码:

 select driver_sku, sold_sku, class_rk, sold_count,
 row_number() over(partition by driver_item_id order by class_rk, sold_count  desc) as rank from data_table;

2 个答案:

答案 0 :(得分:1)

根据您描述问题的方式,您似乎希望按class_rk进行分区:

select driver_sku, sold_sku, class_rk, sold_count,
       row_number() over(partition by driver_item_id, class_rk
                         order by sold_count desc
                        ) as rank
from data_table;

但是,这不符合预期的结果。

编辑:

根据您描述问题的方式,您似乎希望按class_rk进行分区并更改order by

select t.*
from (select driver_sku, sold_sku, class_rk, sold_count,
             row_number() over (partition by driver_item_id, class_rk
                                order by sold_count desc
                               ) as rank
      from data_table
     ) t
order by rank, class_rk

如果你真的想要枚举它们:

select t.*,
       row_number() over (partition by driver_sku, rank
                          order by sold_count desc) as newcol
from (select driver_sku, sold_sku, class_rk, sold_count,
             row_number() over (partition by driver_item_id, class_rk
                                order by sold_count desc
                               ) as rank
      from data_table
     ) t
order by rank, class_rk

答案 1 :(得分:0)

根据您的评论,听起来您只想为每个class_rk创建一条记录。我想这可能是你正在寻找的东西:

SELECT driver_sku, sold_sku, class_rk, max(sold_count)
FROM <TABLE>
GROUP BY driver_sku, class_rk
ORDER_BY class_rk

但是如果你想要在你的问题中订购,我认为你必须做这样的事情:

with ranked as (
    SELECT driver_sku, sold_sku, class_rk, sold_count,
        row_number() over(partition by driver_sku, class_rk order by sold_count desc) as rank
    FROM <TABLE>    
)

SELECT driver_sku, sold_sku, class_rk, sold_count
FROM ranked
GROUP BY driver_sku, rank
ORDER BY class_rk
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