如何在基于类的视图中使用user_passes_test装饰器?

时间:2015-04-16 18:06:25

标签: python django python-2.7 decorator python-decorators

我尝试在允许用户查看特定用户设置页面之前检查某些条件。我试图使用user_passes_test装饰器来实现这一点。该函数位于基于类的视图中,如下所示。我正在使用方法装饰器来装饰视图中的get_initial函数。

class UserSettingsView(LoginRequiredMixin, FormView):
    success_url = '.'
    template_name = 'accts/usersettings.html'

    def get_form_class(self):
        if self.request.user.profile.is_student:
            return form1
        if self.request.user.profile.is_teacher:
            return form2
        if self.request.user.profile.is_parent:
            return form3

    @method_decorator(user_passes_test(test_settings, login_url='/accounts/usertype/'))
    def get_initial(self):
        if self.request.user.is_authenticated():
            user_obj = get_user_model().objects.get(email=self.request.user.email)
            if user_obj.profile.is_student:
                return { ..........
       ...... .... 

以下是test_settings函数:

def test_settings(user):
    print "I am in test settings"
    if not (user.profile.is_student or user.profile.is_parent or user.profile.is_teacher):
        return False
    else:
        return True

我在装饰者处遇到以下错误。

File "../django/core/handlers/base.py", line 111, in get_response
  response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "../django/views/generic/base.py", line 69, in view
  return self.dispatch(request, *args, **kwargs)
File "../braces/views.py", line 107, in dispatch
  request, *args, **kwargs)
File "../django/views/generic/base.py", line 87, in dispatch
  return handler(request, *args, **kwargs)
File "../django/views/generic/edit.py", line 162, in get
  form = self.get_form(form_class)
File "../django/views/generic/edit.py", line 45, in get_form
  return form_class(**self.get_form_kwargs())
File "../django/views/generic/edit.py", line 52, in get_form_kwargs
  'initial': self.get_initial(),
File "../django/utils/decorators.py", line 29, in _wrapper
  return bound_func(*args, **kwargs)
TypeError: _wrapped_view() takes at least 1 argument (0 given)

我不确定如何解决此错误。我在错误的功能上应用装饰器吗?任何线索都会有所帮助。

1 个答案:

答案 0 :(得分:16)

Django 1.9具有基于类视图的身份验证混合。您可以按如下方式使用UserPassesTest mixin。

from django.contrib.auth.mixins import LoginRequiredMixin, UserPassesTestMixin

class UserSettingsView(LoginRequiredMixin, UserPassesTestMixin, View):
    def test_func(self):
        return test_settings(self.request.user)

    def get_login_url(self):
        if not self.request.user.is_authenticated():
            return super(UserSettingsView, self).get_login_url()
        else:
            return '/accounts/usertype/'

请注意,在这种情况下,您必须覆盖get_login_url,因为您要根据用户是否未登录或登录但未通过测试而重定向到其他网址。

对于Django 1.8及更早版本,您应该装饰dispatch方法,而不是get_initial

@method_decorator(user_passes_test(test_settings, login_url='/accounts/usertype/')) 
def dispatch(self, *args, **kwargs):
    return super(UserSettingsView,  self).dispatch(*args, **kwargs)