Question

我正在尝试将数据框中的所有数字转换为浮点数。到目前为止，我已经取得了成功，除了百分之一列。我得到错误'浮动的无效文字：0.00％'但它似乎适用于其他一切。到目前为止，这是我的代码：

def clean():
    rawdata = concat()
    rawdata = rawdata[['Channel','Advertiser Domain','Bids','Imp.','Avg. Bid CPM (USD)','Revenue (USD)','eCPM (USD)','Wins','Date']]     
    rawdata[['Bids','Imp.','Avg. Bid CPM (USD)','Revenue (USD)','eCPM (USD)','Wins']] \
    = rawdata[['Bids','Imp.','Avg. Bid CPM (USD)','Revenue (USD)','eCPM (USD)','Wins']].\
    replace([',','%'],'').astype(float)
    return rawdata

解决了：

def clean():
    rawdata = concat()
    rawdata = rawdata[['Channel','Advertiser Domain','Bids','Imp.','Avg. Bid CPM (USD)','Revenue (USD)','eCPM (USD)','Wins','Date']]     
    for col in ['Bids','Imp.','Wins']:
        rawdata[col] = rawdata[col].str.replace(',','').str.replace('%','')
    for com in ['Bids','Imp.','Avg. Bid CPM (USD)','Revenue (USD)','eCPM (USD)','Wins']:
        rawdata[com] = rawdata[com].astype(float)
    return rawdata.sort('Revenue (USD)', ascending=False)

Answer 1

修改您的replace以包含regex=True：

rawdata = rawdata.replace([',','%'],'', regex=True).astype('float')

如何将数据框中的对象转换为浮点数？

1 个答案: