Question

按字母数排序。检查以相同字母开头的单词。检查一个单词是否完全出现在另一个单词中。当两个单词都以相同的字母开头时。如果它完全存在。只显示第一个单词和忽略第二个单词

var arraylist = ["running", "walking", "standing", "writing", "waiting", "sleeping", "reading", "washing", "sitting", "riding", "shopping", "singing", "painting", "watching", "swimming", "pulling", "smoking", "pushing", "drinking", "dancing", "cooking", "crying   ", "eating", "smiling","run", "walk", "push", "cook", "cry", "eat"];

使用javascript / jquery预期输出：

我需要删除这些词：跑步，走路，推，做饭，哭，吃。

var arrayList = ["run", "walk", "standing", "writing", "waiting", "sleeping", "reading", "washing", "sitting", "riding", "shopping", "singing", "painting", "watching", "swimming", "pulling", "smoking", "push", "drinking", "dancing", "cook", "cry", "eat", "smiling","run", "walk", "push", "cook", "cry", "eat"];

Answer 1

对于@Grimbode提到的案例来自OP

检查一个单词是否完全出现在另一个单词
中

所以微笑 完全存在 微笑

所以这个解决方案可能会有所帮助

function filter(arr) {
  arr.sort(function(a, b) {
    return a.length - b.length;
  })
  return arr.reduce(function(acc, el) {
    if (!acc.some(function(e) {
      return el.startsWith(e);
    })) {
      acc.push(el);
    }
    return acc;
  }, []);
}

注意：来自mdn

的旧浏览器的Polyfill

if (!String.prototype.startsWith) {
    String.prototype.startsWith = function(searchString, position) {
        position = position || 0;
        return this.lastIndexOf(searchString, position) === position;
    };
}

＆＃13;

if (!String.prototype.startsWith) {
    String.prototype.startsWith = function(searchString, position) {
        position = position || 0;
        return this.lastIndexOf(searchString, position) === position;
    };
}

var arraylist = ["running", "walking", "standing", "writing", "waiting", "sleeping", "reading", "washing", "sitting", "riding", "shopping", "singing", "painting", "watching", "swimming", "pulling", "smoking", "pushing", "drinking", "dancing", "cooking", "crying   ", "eating", "smiling", "run", "walk", "push", "cook", "cry", "eat"];

function filter(arr) {
  arr.sort(function(a, b) {
    return a.length - b.length;
  })
  return arr.reduce(function(acc, el) {
    if (!acc.some(function(e) {
      return el.startsWith(e);
    })) {
      acc.push(el);
    }
    return acc;
  }, []);
}
document.getElementById('before').innerHTML = JSON.stringify(arraylist);

document.getElementById('result').innerHTML = JSON.stringify(filter(arraylist));

＆＃13;

<div><span>initial array:</span><span id="before"></span>
  <div>
    <div><span>result array:</span><span id="result"></span>
      <div>

＆＃13;

Answer 2

检查一下。虽然这在@Grimbode

提到的情况下不起作用

＆＃13;

var sentence = "Did Marying go to the store today?";
var arraylist = ["running", "walking", "standing", "writing", "waiting", "sleeping", "reading", "washing", "sitting", "riding", "shopping", "singing", "painting", "watching", "swimming", "pulling", "smoking", "pushing", "drinking", "dancing", "cooking", "crying   ", "eating", "smiling","run", "walk", "push", "cook", "cry", "eat"];


function myFunction() {
    $.each(arraylist, function(index,item){
       $.each(arraylist,function(indexInner, item1){
           if( index != indexInner && item1 && item && item1.substring(0,(item.length)) == item){  
             arraylist[indexInner] = arraylist[index];
             arraylist[index] = false;
           }
       });
    });
    arraylist = cleanArray(arraylist);
    document.getElementById("demo").innerHTML = arraylist;
}


function cleanArray(actual){
  var newArray = new Array();
  for(var i = 0; i<actual.length; i++){
      if (actual[i]){
        newArray.push(actual[i]);
    }
  }
  return newArray;
}

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<p>Click the button to add elements to the array.</p>

<button onclick="myFunction()">Try it</button>
<p id="demo"></p>

＆＃13;

从数组逻辑中删除项目 - 呈现时态并呈现连续时态

2 个答案: