PHP查询一直失败

时间:2015-04-23 04:28:28

标签: php mysql

<html>
<head>
  <title>Inserts</title>
</head>

<body>
  <h1>Adding a User</h1>

  <form action="insert1.php" method="post">

    Gamertag:<br />
    <input name="insertfield1" type="text">
    <br />
    Bio:<br />
    <input name="insertfield2" type="text">
    <br />
    Membership:<br />
    <input name="insertfield3" type="text">
    <br />
    Gamerscore:<br />
    <input name="insertfield4" type="number">
    <br />
    Email:<br />
    <input name="insertfield5" type="text">
    <br />
    Name:<br />
    <input name="insertfield6" type="text">
    <br />
    Location:<br />
    <input name="insertfield7" type="text">
    <br />
    Friend:<br />
    <input name="insertfield8" type="text">
    <br />
    <input type="submit" value="Insert">
  </form>

</body>
</html>

结束HTML 开始php

</head>
<body>
<h1>Insert Test Results</h1>
<?php
  // create short variable names
  $insertfield1=$_POST["insertfield1"];
  $insertfield2=$_POST["insertfield2"];
  $insertfield3=$_POST["insertfield3"];
  $insertfield4=$_POST["insertfield4"];
  $insertfield5=$_POST["insertfield5"];
  $insertfield6=$_POST["insertfield6"];
  $insertfield7=$_POST["insertfield7"];
  $insertfield8=$_POST["insertfield8"];


  //use trim function to strip whitespace inadvertently entered at beginning or end of insert term
  $insertfield1= trim($insertfield1);
  $insertfield2= trim($insertfield2);
  $insertfield3= trim($insertfield3);
  $insertfield4= trim($insertfield4);
  $insertfield5= trim($insertfield5);
  $insertfield6= trim($insertfield6);
  $insertfield7= trim($insertfield7);
  $insertfield8= trim($insertfield8);


echo "First insert term entered: $insertfield1";
echo "<br>"; 

echo "Second insert term entered: $insertfield2";
echo "<br>"; 

echo "Third insert term entered: $insertfield3";
echo "<br>"; 

echo "Fourth insert term entered: $insertfield4";
echo "<br>"; 

echo "Fifth insert term entered: $insertfield5";
echo "<br>"; 

echo "Sixth insert term entered: $insertfield6";
echo "<br>"; 

echo "Seventh insert term entered: $insertfield7";
echo "<br>"; 

echo "Eight insert term entered: $insertfield8";
echo "<br>"; 


  if (!$insertfield1)
  {
     echo 'You have not entered insert details.  Please go back and try again.';
     exit;
  }

  // connect to database
  $link=mysqli_connect("yourMysqlServer", "usernameHere", "myPassword", "myDatabase")
     or die('Could not connect ');
  echo "Connected successfully <br>";

  // insert new data into table
  $result = mysqli_query($link,"INSERT INTO userprofile values ('$insertfield1', '$insertfield2', '$insertfield3', $insertfield4, '$insertfield5', '$insertfield6', '$insertfield7', '$insertfield8' ) " )       
      or die("Query failed ");
  echo "query ok\n";

  $num_results = mysqli_num_rows($result);

  echo '<p>Number of rows inserted in userprofile: '.$num_results.'</p>';

  // query table to show new data inserted
  $result = mysqli_query($link,"SELECT * from userprofile")  
      or die("Query failed ");
  echo "query ok\n";

  $num_results = mysqli_num_rows($result);

  echo '<p>New number of rows in userprofile: '.$num_results.'</p>';

 // show results of table with new data inserted
  echo " <table border='1'>\n";
  while ($line = mysqli_fetch_array($result, MYSQL_ASSOC)) {
     echo "\t<tr>\n";
     foreach ($line as $col_value) {
        echo "\t\t<td>$col_value</td>\n";
     }
     echo "\t</tr>\n";
}
echo "</table>\n";


//Free result set
mysqli_free_result($result);

//close connection
mysqli_close($link);

?>
</body>
</html>

由于某些原因,这些没有正确地相互通信。我的假设是我的PHP代码有问题。我可以告诉你我可以正确连接,但当我尝试插入时没有,它说查询失败。

1 个答案:

答案 0 :(得分:1)

1)尝试使用此格式

mysqli_query($link,"INSERT INTO userprofile (col1,col2,col3) VALUES ('value1','value2','value3')");

并确保你不会错过任何事情。

2)尝试将gamescore的值更改为varchar,并在插入时进行更改。

3)检查每个表列中的允许值长度,确保输入未超过允许的长度

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