匹配两个不同文件中最接近的值并打印特定列

时间:2015-04-23 15:14:29

标签: bash awk

大家好我有两个文件,每个文件有N列和M行。

File1中

1 2 4 6 8
20 4 8 10 12
15 5 7 9 11

文件2

1 a1 b1 c5 d1
2 a1 b2 c4 d2
3 a2 b3 c3 d3
19 a3 b4 c2 d4
14 a4 b5 c1 d5

我需要的是搜索第1列中最接近的值,并在输出中打印特定列。所以例如输出应该是:

文件3

1 2 4 6 8
1 a1 b1 c5 d1
20 4 8 10 12
19 a3 b4 c2 d4
15 5 7 9 11
14 a4 b5 c1 d5

由于1 = 1,19最接近20和14到15,输出是那些行。 如何在awk或任何其他工具中执行此操作?

帮助!

这就是我现在所拥有的:

echo "ARGIND == 1 {
s1[\$1]=\$1;
s2[\$1]=\$2;
s3[\$1]=\$3;
s4[\$1]=\$4;
s5[\$1]=\$5;
}
ARGIND == 2 {
bestdiff=-1;
for (v in s1)
if (bestdiff < 0 || (v-\$1)**2 <= bestdiff) 
{
s11=s1[v];
s12=s2[v];
s13=s3[v];
s14=s4[v];
s15=s5[v];
bestdiff=(v-\$1)**2;
if (bestdiff < 2){
print \$0
print s11,s12,s13,s14,s15}}">diff.awk
awk -f diff.awk file2 file1

输出:

1 2 4 6 8
1 a1 b1 c5 d1
20 4 8 10 12
19 a3 b4 c2 d4
15 5 7 9 1
14 a4 b5 c1 d5
1 2
1 1
14 15

我不知道为什么最后三行。

1 个答案:

答案 0 :(得分:1)

我试图给出回答的方式结束了:

function closest(b,i) { # define a function
  distance=999999; # this should be higher than the max index to avoid returning null
  for (x in b) { # loop over the array to get its keys
    (x+0 > i+0) ? tmp = x - i : tmp = i - x # +0 to compare integers, ternary operator to reduce code, compute the diff between the key and the target
    if (tmp < distance) { # if the distance if less than preceding, update
      distance = tmp
      found = x # and save the key actually found closest
    }
  }
  return found  # return the closest key
}

{ # parse the files for each line (no condition)
   if (NR>FNR) { # If we changed file (File Number Record is less than Number Record) change array
     b[$1]=$0 # make an array with $1 as key
   } else {
     akeys[max++] = $1 # store the array keys to ensure order at end as for (x in array) does not guarantee the order
     a[$1]=$0 # make an array with $1 as key
   }
}

END { # Now we ended parsing the two files, print the result
  for (i in akeys) { # loop over the first file keys
    print a[akeys[i]] # print the value for this file
    if (akeys[i] in b) { # if the same key exist in second file
      print b[akeys[i]] # then print it
    } else {
      bindex = closest(b,akeys[i]) # call the function to find the closest key from second file
      print b[bindex] # print what we found
    }
  }
}

我希望这个评论足够明确,如果需要,请随时发表评论。

警告如果第二个文件中有大量行,这可能会变得非常慢,因为第二个数组将针对第一个文件的每个键解析,而第二个文件中不存在第二个文件。<强> /警告

给出您的样本输入a1和a2:

$ mawk -f closest.awk a1 a2
1 2 4 6 8
1 a1 b1 c5 d1
20 4 8 10 12
19 a3 b4 c2 d4
15 5 7 9 11
14 a4 b5 c1 d5
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