是否有一个Python 2等效的Javascripts confirm()命令?

时间:2015-04-25 17:15:47

标签: javascript python

简短版只是一个问题。

更长的版本: 我正在尝试通过Codecademy学习Javascript,同时尝试重新学习Python 2。我刚刚完成了选择你自己的冒险故事。

在下面的代码中,除了第2行中的confirm命令之外,我可以弄清楚除了代码之外如何轻松地调整Python 2的所有内容。

// Check if the user is ready to play!
confirm("It's gametime!");
var age = prompt("What's your age");
if (age < 13)
{
console.log("You're really young, but go play");
}
else
{
    console.log("You're old enough. Start playing");
}
console.log("You are at a Justin Bieber concert, and you hear this lyric 'Lace my shoes off, start racing.'");
console.log("Suddenly, Bieber stops and says, 'Who wants to race me?'");
var userAnswer = prompt("Do you want to race Bieber on stage?");
if (userAnswer === "yes")
{
    console.log("You and Bieber start racing. It's neck and neck! You win by a shoelace!");
}
else
{
    console.log("Oh no! Bieber shakes his head and sings 'I set a pace, so I can race without pacing.'");
}
var feedback = prompt("Rate this game from 1-10");
if (feedback > 8)
{
    console.log("Thank you! We should race at the next concert!");
}
else
{
    console.log("I'll keep practicing coding and racing.");
} 

我很感激任何帮助。非常感谢。

1 个答案:

答案 0 :(得分:1)

如果您尝试在命令行捕获用户的输入,则可以使用raw_input功能:

age = raw_input("What's your age?\n")
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