dict获得了密钥years，并且每年它都列出了当年所有12个月的所有温度。我的目标是从一年开始打印一张表，然后是每个月的新行和当月的临时值。
主要是使用(ATH)标记所有年份的最高温度，并使用(YearHighest)标记每年的最高温度。
My current code:
temp_dict= {
"2010": [2, 3, 4, 5, 7, 3, 20, 29, 34, 2, 10, 1],
"2011": [2, 7, 4, 5, 9, 3, 20, 9, 34, 2, 10, 10]
}
for key in temp_dict:
print("Year",key,":")
x=0
for temps in temp_dict[key]:
x=x+1
print("Month "+str(x)+":%3d"%temps)
print()
我不确定如何制作最大功能，我正在考虑这样的事情，但我无法让它发挥作用：
for key in temp_dict:
ATH = temp_dict[key]
YearHigh = temp_dict[key][0]
for temps in temp_dict[key]:
if temps >= temp_dict[key][0]:
YearHigh = temps
if YearHigh >= ATH:
ATH = YearHigh
我希望输出看起来如何：
Year 2011 :
Month1: 2
Month2: 7
Month3: 4
Month4: 5
Month5: 9
Month6: 3
Month7: 20
Month8: 9
Month9: 34 (YearHighest)(ATH)
Month10: 2
Month11: 10
Month12: 10
Year 2010 :
Month1: 2
Month2: 3
Month3: 4
Month4: 5
Month5: 7
Month6: 3
Month7: 20
Month8: 29
Month9: 34 (YearHighest)(ATH)
Month10: 2
Month11: 10
Month12: 1
答案 0 :(得分：4)
Python内置了函数max，它被认为是一种很好的使用方法。
年度最大值：
max(temp_dict["2010"])
所有时间最长：
max(sum(temp_dict.values(), []))
sum(lists, [])列出扁平化，相当于
[] + lists[0] + lists[1]...
答案 1 :(得分：1)
Python有一个你可以使用的内置函数max：
for key in temp_dict:
print("Year", key,":")
temps = temp_dict[key]
max_temp = max(temps)
max_index = temps.index(max_temp)
for index, temps in enumerate(temps):
r = "Month "+str(index+1)+":%3d"%temps
if index == max_index:
r += "(YearHighest)(ATH)"
print(r)
答案 2 :(得分：0)
您可以尝试这样的事情：
temp_dict= {
"2010": [2, 3, 4, 5, 7, 3, 20, 29, 34, 2, 10, 1],
"2011": [2, 7, 4, 5, 9, 3, 20, 9, 34, 2, 10, 10]
}
# defines the max of all years with a list comprehension
global_max_temp = max([ max(year_temps) for year_temps in temp_dict.values() ])
# iterates through each year
for year, temps in temp_dict.items():
print("Year {}".format(year))
for i, temp in enumerate(temps):
# prepares the output
temp_string = ["Month{}: {}".format(i+1, temp)]
# builds a list of flags to be displayed
flags = []
if temp == max(temps):
# max in year flag
flags.append("YearHighest")
if temp == global_max_temp:
# absolute max flag
flags.append("ATH")
# joins temp_string and flags in a single line and prints it
print(" ".join(temp_string + [ "({})".format(flag) for flag in flags ]))
Python文档中的有用链接：enumerate，list comprehensions，max
答案 3 :(得分：-1)
这是我的代码。
temp_dict= {
"2010": [2, 3, 4, 5, 7, 3, 20, 29, 34, 2, 10, 1],
"2011": [2, 7, 4, 5, 9, 3, 20, 9, 34, 2, 10, 10]
}
# Find the highest temp of all years
ath = max([ max(v) for v in temp_dict.values()])
for key in temp_dict:
# Output Year
print("Year{k}:".format(k=key))
x=0
# Find max
max_value = max(temp_dict[key])
for temps in temp_dict[key]:
# Output Month
x=x+1
s = "Month {x}:{v:3d}".format(x=str(x), v=temps)
# Tag the max value
if max_value == temps:
s += "(YearHighest)"
if ath == temps:
s += "(ATH)"
print(s)
print()
这是我的输出。
Year2010:
Month 1: 2
Month 2: 3
Month 3: 4
Month 4: 5
Month 5: 7
Month 6: 3
Month 7: 20
Month 8: 29
Month 9: 34(YearHighest)(ATH)
Month 10: 2
Month 11: 10
Month 12: 1
Year2011:
Month 1: 2
Month 2: 7
Month 3: 4
Month 4: 5
Month 5: 9
Month 6: 3
Month 7: 20
Month 8: 9
Month 9: 34(YearHighest)(ATH)
Month 10: 2
Month 11: 10
Month 12: 10
这里需要使用max函数。它可以快速从列表的数字中获得最大值。