Question

我正在尝试执行查询，这在JPA中运行正常，但这些不适用于Open JPA，您有什么想法吗？

String iNString;
try {
            String query = "Delete FROM  Table1o WHERE o.Pk1 IN('"+ iNString+ "') and o.countryCode = '"+ countryCode+ "'";
            entityManager().createQuery(query).executeUpdate();
            LOGGER.info("Delete Query-----------------: " + query);

        } 
catch( Exception exception ) {
            throw new DataLayerException(exception.getMessage(),exception);
        }

错误：-org.springframework.dao.InvalidDataAccessApiUsageException：没有找到类型为“class java.lang.String”的元数据。班级不是增强;嵌套异常是org.apache.openjpa.persistence.ArgumentException：否找到类型为“class java.lang.String”的元数据。班级不是增强。

Answer 1

EntityManager em = Relationship.entityManager（）; StringBuilder sbQueryString = new StringBuilder（＆＃34; SELECT o FROM table AS o WHERE 1 = 1＆＃34;）; if（StringUtils.isNotEmpty（DTO.getNameEng（）））{ sbQueryString.append（＆＃34; AND LOWER（o.NameEng）LIKE：_NAME_ENG＆＃34;）; }

    sbQueryString.append(" order by o.relationshipNameEng");
    TypedQuery<Relationship> q = em.createQuery(sbQueryString.toString(), User.class);
    if (StringUtils.isNotEmpty(DTO.getRelationshipNameEng())) {
        q.setParameter("_NAME_ENG", "%" + DTO.getNameEng().toLowerCase() + "%");
    }

在JPQL typedquery中解析IN-Clause

1 个答案: