Question

我有两个数组：

1）第一个数组：

array(

    [0] => array(
              [code] => code_1
              [value] => xxx
    [1] => array(
              [code] => code_2
              [value] => xxx     
    [2] => array(
              [code] => code_3
              [value] => xxx

2）第二个数组：

array(

    [0] => array(
              [settingcode] => code_1
              [value] => xxx
    [1] => array(
              [settingcode] => code_2
              [value] => xxx     
    [2] => array(
              [settingcode] => code_3
              [value] => xxx
    [3] => array(
              [settingcode] => code_4
              [value] => xxx     
    [4] => array(
              [settingcode] => code_5
              [value] => xxx

如何将array2中的两个缺失项（code_4和code_5）添加到array1？

谢谢！

UPD。

对不起，我需要澄清一下这个问题。我需要结果数组看起来像：

array(

    [0] => array(
              [code] => code_1
              [value] => xxx
    [1] => array(
              [code] => code_2
              [value] => xxx     
    [2] => array(
              [code] => code_3
              [value] => xxx
    [3] => array(
              [code] => code_4
              [value] => xxx     
    [4] => array(
              [code] => code_5
              [value] => xxx

Answer 1

array_merge

Answer 2

function add($from, $to)
{
 foreach($from as $key => $value)
 {
  if($to[$key] == "")
       $to[$key] = $value;
 }
 return $to;
}

array_merge是更好的方法，但是

Answer 3

如果你可以使用数组的键来识别值，那么这将起作用

$resulting_array = $array2 + $array1;

将项目从一个数组添加到另一个数组

3 个答案: