我'想要根据名为id的对象过滤NSARRAY
,我想要过滤并想要成为NSARRAY
中的第一个特定的ID ID。
我将以下ID存储为NSNUMEBR
NSNumber *A = [NSNumber numberWithInt:1122];
NSNumber *B = [NSNumber numberWithInt:1345];
NSNumber *C = [NSNumber numberWithInt:1667];
NSNumber *D = [NSNumber numberWithInt:1223];
NSNumber *E = [NSNumber numberWithInt:1213];
NSNumber *F = [NSNumber numberWithInt:1123];
NSNumber *G = [NSNumber numberWithInt:1555];
NSNumber *H = [NSNumber numberWithInt:1666];
NSNumber *I = [NSNumber numberWithInt:1567];
这些是我想要过滤的ID并希望成为我NSARRAY
的第一个ID(可以NSMutableArray
进行操作)
编辑1:
NSARRAY基本上将id对象作为
Ids = [dict valueForKey:@"id"];
选择性ID存储在NSNUMBER A到I
中答案 0 :(得分:0)
目前还不清楚你在问什么,正如投票和评论所表明的那样。但是,让我们看看我们是否可以提供帮助。我认为以下伪代码算法是您要求的:
MutableArray frontItems, rearItems;
for every item in sourceArray
if item["id"] is in the collection of specific IDs
then add item to end of frontItems
else add item to end of rearItems
add rearItems to end of frontItems to give result
在Objective-C中写一下,我认为你有你想要的东西。
HTH
答案 1 :(得分:0)
// Creat数组包含所有项目:A-> I
NSNumber *A = [NSNumber numberWithInt:1122];
NSNumber *B = [NSNumber numberWithInt:1345];
NSNumber *C = [NSNumber numberWithInt:1667];
NSNumber *D = [NSNumber numberWithInt:1223];
NSNumber *E = [NSNumber numberWithInt:1213];
NSNumber *F = [NSNumber numberWithInt:1123];
NSNumber *G = [NSNumber numberWithInt:1555];
NSNumber *H = [NSNumber numberWithInt:1666];
NSNumber *I = [NSNumber numberWithInt:1567];
NSMutableArray *arr = [[NSMutableArray alloc] initWithObjects:A,B,C,...,I, nil];
for (NSNumber *idx in arr) {
// To do
}