使用NSURLConnection连续发送100+请求，并在发送下一个请求之前等待每个响应

Question

如何使用NSURLConnection连续发送100+请求并在发送下一个请求之前等待每个响应，同时发送100个循环的请求，仅在前四或五个请求时收到响应，其余请求在请求超时时获得响应，请帮我提供一些示例代码或参考资料

NSURLRequest *request=[NSURLRequest requestWithURL:[NSURL URLWithString:[str stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]];
_Connection=[[NSURLConnection alloc]initWithRequest:request delegate:self startImmediately:YES];

Answer 1

试试这个，

调用startGenerator方法，将0值作为您要开始的参数。

+(void)startGenerator:(int)counter { 

     NSURLRequest *request=[NSURLRequest requestWithURL:[NSURL URLWithString:[str stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]];
    [NSURLConnection request
                                           queue:[NSOperationQueue currentQueue]
                               completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
           if (error == nil) {
              //Your Response parse and other stuff
              dispatch_after(dispatch_time(DISPATCH_TIME_NOW, 5 * NSEC_PER_SEC), dispatch_get_main_queue(), ^{
                    // Make next request after  5 second after completion of current request.  
                    counter++;
                    if (counter<limitOfURL)
                         [self startGenerator];
              });
           }
   }];

希望这对你有所帮助。