Question

我怎样才能以这种格式回应这个json？

123456789 - mypage3 - 2015-05-06 09:34:02
          - mypage2 - 2015-05-06 09:34:02
          - mypage1 - 2015-05-06 09:34:02

999999    - mypage4 - 2015-05-06 09:34:02

这是JSON

{"hash":"123456789","pages":[{"page":"mypage3","last_access_time":"2015-05-06 09:34:02"},{"page":"mypage2","last_access_time":"2015-05-06 09:34:02"},{"page":"mypage1","last_access_time":"2015-05-06 09:34:02"}]}

{"hash":"999999","pages":[{"page":"mypage4","last_access_time":"2015-05-06 09:34:02"}]}

以下是我现在所拥有的：

$appResult = array();

while($row = mysql_fetch_array($sql)) {
    $json_res_obj = json_decode($row['json_prt']);  
    echo $row[json_prt];
}

Answer 1

在这里考虑这个PHP代码，它仅适用于第一个JSON字符串，但您明白了这一点：

<?php 

$json = '{
    "hash": "123456789",
    "pages": [
        {
            "page": "mypage3",
            "last_access_time": "2015-05-06 09:34:02"
        },
        {
            "page": "mypage2",
            "last_access_time": "2015-05-06 09:34:02"
        },
        {
            "page": "mypage1",
            "last_access_time": "2015-05-06 09:34:02"
        }
    ]
}';

$data = json_decode($json,true);


echo $data['hash'] . " - ";

foreach($data['pages'] as $rows) {
  echo $rows['page'] . " - " . $rows['last_access_time'] . "<br>";
}

?>

Answer 2

使用此代码

    <?php

    $data = '{"hash":"123456789","pages":[{"page":"mypage3","last_access_time":"2015-05-06 09:34:02"},{"page":"mypage2","last_access_time":"2015-05-06 09:34:02"},{"page":"mypage1","last_access_time":"2015-05-06 09:34:02"}]}';
    $data = json_decode($data);
    echo $data->hash . "<br>";
    $pages = $data->pages;
    if(isset($data->pages)){
      foreach($pages as $key => $value){
            echo $value->page . "-" . $value->last_access_time . "<br>";
     }
   }

?>

Answer 3

您可以使用此代码添加一些格式

$row['json_prt'] = '{"hash":"123456789","pages":[{"page":"mypage3","last_access_time":"2015-05-06 09:34:02"},{"page":"mypage2","last_access_time":"2015-05-06 09:34:02"},{"page":"mypage1","last_access_time":"2015-05-06 09:34:02"}]}';
    $json_res_obj = json_decode($row['json_prt']);  

    echo '<pre>';
    foreach($json_res_obj->pages as $page) 
        echo ' - '.$page->page.' - '.$page->last_access_time.'<br>';

更新：

while($row = mysql_fetch_array($sql)) {
     $json_res_obj = json_decode($row['json_prt']);  

        echo '<pre>';
        foreach($json_res_obj->pages as $page) 
            echo ' - '.$page->page.' - '.$page->last_access_time.'<br>';
}

如何在此特定输出中回显此JSON？

3 个答案: