Question

我尝试创建一个基于列名对项目进行分组的数据表。为了正确填充表格，我需要使用父子关系格式化JSON，但遇到了麻烦。我将通过PHP从MSSQL中获取数据。

$ xmodmap -e "remove Control = Control_L"

我需要像这样格式化的JSON，父对象位于＆＃34;数据＆＃34;和孩子们在孩子们的照顾下＃34;我很难搞清楚我是否需要进行两个单独的查询，一个用于父级的汇总数据，另一个用于子行。任何帮助都会被提及。

编辑以添加PHP ：

+---------------+-------+--------------+------------+------------+--------+
| ACTIVITY_NAME | GROUP |  START_DATE  |  END_DATE  | COMPLETED  | TOTAL  |
+---------------+-------+--------------+------------+------------+--------+
|          Test |     1 |  04/30/2015  |  05/01/2015|        10  |    15  |
|          Test |     2 |  04/30/2015  |  05/01/2015|        20  |    25  |
|         Test2 |     1 |   05/2/2015  |  05/03/2015|        30  |    35  |
|         Test2 |     2 |   05/2/2015  |  05/03/2015|        40  |    45  |
|         Test2 |     3 |   05/2/2015  |  05/03/2015|        50  |    55  |
+---------------+-------+--------------+------------+------------+--------+

我需要这种格式： JSON blob：https://jsonblob.com/554b958be4b05c281ae9707e

<?php 
include("connect.php");

if( $conn === false ) {
   echo "Could not connect.\n";
   die( print_r( sqlsrv_errors(), true));
}
/* Set up and execute the query. */
$sql = "<QUERY>";
$stmt = sqlsrv_query( $conn, $sql);

do {
     while ($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC)) {
     $json[] = $row;

     }
} while ( sqlsrv_next_result($stmt) );
foreach ($json as $result) {
    $data[$result['ACTIVITY_NAME']]['children'] = $result;
}
echo json_encode($data);
?>

Answer 1

我建议您使用两个查询，然后将数据放入与您的格式匹配的数组中，并将其json_encode以生成所需的结果。

您可能需要查看SQL Server recursive query

Answer 2

您似乎正在通过ACTIVITY_NAME进行分组，如果是这种情况并且您不想进行其他查询，则可以先创建一个关联数组：

foreach ($results as $result) {
    $data[$result['ACTIVITY_NAME']]['children'] = $result;
}

然后你可以使用该数组迭代子数来计算数据，如MAINTENANCE_GROUP，COMPLETED和TOTAL;

完成所有这些后，您可以使用array_values来获取非关联数组。

Answer 3

以下是工作脚本的样子：

<?php 
include("connect.php");

if( $conn === false ) {
   echo "Could not connect.\n";
   die( print_r( sqlsrv_errors(), true));
}
/* Set up and execute the query. */
$sql = "<query> ";
$stmt = sqlsrv_query($conn, $sql);

// This is where the data will be organized.
// It's better to always initialize the array variables before putting data in them
$data = array();

// Get the rows one by one
while ($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC)) {
    // Extract the activity name; we want to group the rows by it
    $name = $row['ACTIVITY_NAME'];
    $group = '';
    $sdate = '';
    $edate = '';
    $completed = '';
    $total = '';
    $perc = '';

    // Check if this activity was encountered before
    if (! isset($data[$name])) {
        // No, this is the first time; we will make room for it, first
        $data[$name] = array(
            // Remember the name
            'ACTIVITY_NAME' => $name,
            'MAINTENANCE_GROUP' => $group,
            'START_DATE' => $sdate,
            'END_DATE' => $edate,
            'COMPLETED' => $completed,
            'TOTAL_CLUSTERS' => $total,
            'COMPLETE_PERC' => $perc,
            // No children yet
            'children' => array(),
        );
    }
    // Put the row into the list of children for this activity
    $data[$name]['children'][] = $row;
}

// Here, the entries in $data are indexed by the values they also have in                  'ACTIVITY_NAME'
// If you want them numerically indexed, all you have to do is:
$data = array_values($data);
echo json_encode(array('data' => $data));
//echo json_encode($data);
?>

通过PHP从SQL进行JSON格式化

3 个答案: