C.检查浮点数的输入是否为一定数量的小数位

时间:2015-05-10 14:05:51

标签: c error-checking

早上好。我编写的代码用于计算事务中给出的更改量,仅更改部分,忽略纸张更改。我想做一个错误检查,以确保用户输入的#不超过2位小数。这是我的代码。

#include <stdio.h>
#include <stdlib.h>
void intro();
void instructions();
void getvalues(float *owe, float *paid);
float totalchange(float *owe, float *paid);
void quarters (float *change);
void dimes (float *change);
void nickels (float *change);
void pennies (float *change);

int main()
{
    float owe = 0.0, paid = 0.0, change;
    int a = 2;
    intro();
    instructions();

        printf("Would you like to continue?\n1: Continue\n0: Exit\n");
        scanf("%i", &a);
        if (a== 0)
            exit(0);

        while (a == 1){
            getvalues(&owe, &paid);
            while (owe > paid)
                getvalues(&owe, &paid);
            change = totalchange(&owe, &paid);
            quarters (&change);
            dimes (&change);
            nickels (&change);
            pennies (&change);

            printf("Would you like to make another calculation?\n1: Continue\n0: Exit\n");
            scanf("%i", &a);
    }

    return 0;
}

void intro(){
    printf("Program: Homework 1 Part 1 :: Change Calculator\nAuthor: Jason Golightly\nDate:5-13-15\nVersion 1.0\n\n");
}


void instructions(){
    printf("This program is designed to calculate the coin\nportion of the change given after a purchase.\n");
    printf("When prompted, please enter the purchase amount and the amount paid.\nThe amount paid must exceed the purchase amount.\n");
}

void getvalues(float *owe, float *paid){

        printf("Please enter the amounts in a dollars.cents fashion\n\nPurchase amount?\n");
        scanf("%f", owe);
        printf("\nAmount paid?\n");
        scanf("%f", paid);
        printf("\n");
        if (*owe > *paid)
            printf("ERROR. Please enter valid amounts.\n");
        if (*owe == *paid)
            printf("You have given exact change.\n")

}

float totalchange(float *owe, float *paid){
    int a;
    a = (*paid - *owe)*100;
    a = a % 100;
    printf("total change = %i\n",a);
    return a;
}
void quarters (float *change){
    int q;
    q = *change / 25;
    printf("Quarters = %i\n", q);
    *change = *change - 25*q;
}
void dimes (float *change){
    int d;
    d = *change / 10;
    printf("Dimes = %i\n", d);
    *change = *change - 10*d;
}

void nickels (float *change){
    int n;
    n = *change / 5;
    printf("Nickels = %i\n", n);
    *change = *change - 5*n;
}
void pennies (float *change){
    int p;
    p = *change / 1;
    printf("Pennies = %i\n\n", p);
    *change = *change - 1*p;
}

另外,如果你没有注意到,我对编程很新。如果你看到其他任何我可以做得更好的东西,请随时指出。

谢谢,杰森

0 个答案:

没有答案
相关问题