Active Record中的Yii2子查询

时间:2015-05-11 09:50:47

标签: yii yii2

如何将此sql转换为活动记录查询

SELECT * FROM `base_twitter` WHERE id NOT IN (SELECT base_id from base_followers)

3 个答案:

答案 0 :(得分:54)

假设您的模型相应地命名为BaseTwitterBaseFollower,这应该可行:

$subQuery = BaseFollower::find()->select('id');
$query = BaseTwitter::find()->where(['not in', 'id', $subQuery]);
$models = $query->all();

答案 1 :(得分:7)

// SELECT * FROM (SELECT * FROM `user` WHERE `active` = 1) `activeusers`;
$subquery = (new \yii\db\Query)->from('user')->where(['active' => true])
$query = (new \yii\db\Query)->from(['activeusers' => $subquery]);

// subquery can also be a string with plain SQL wrapped in parenthesis
// SELECT * FROM (SELECT * FROM `user` WHERE `active` = 1) `activeusers`;
$subquery = "(SELECT * FROM `user` WHERE `active` = 1)";
$query = (new \yii\db\Query)->from(['activeusers' => $subquery]);

答案 2 :(得分:1)

尝试此查询

$models = BaseTwitter::find()->where('id NOT IN (SELECT base_id from base_followers)')->all();
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