Question

我有一个对象（Department），它将是根元素。它有一个聚合对象（Employee），它有两个特化（Manager和FactoryWorker）。如果我将Employee设置为其中一个专用对象，则只编组Employee对象属性。我很感激任何提示。

e.g。

@XmlRootElement(name="department")
class Department {
   public Department() {}
   private Employee employee;
   public void setEmployee(final Employee val) {
       this.employee = val;
   }
}

class Employee {
   private Long id;
   public Employee() {}
   //getters and setters
}

class Manager extends Employee {
   public Manager() {}
   private Integer numberOfProjects;
   //getters and setters
}
class FactoryWorker extends Employee {
   public FactoryWorker() {}
   private Boolean worksNights;
   //getters and setters
}

仅用于显示编组的代码片段

Deparment department = new Department();
FactoryWorker factoryWorker = new FactoryWorker();
factoryWorker.setId(999);
factoryWorker.setWorksNights(true);

JAXBContext jaxBContext = JAXBContext.newInstance(Department.class);
Marshaller jaxbMarshaller = jaxBContext.createMarshaller();
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.marshal(department, System.out);

JAXB输出：工厂工人的专门属性不在那里。只是父Employee中的值。

<department>
   <employee>
      <id>999</id>
    </employee>
</department>

Answer 1

你需要这样做：

@XmlRootElement(name="Department")
class Department {
    public Department() {}
    @XmlElements({
        @XmlElement(name="Manager", type=Manager.class),
        @XmlElement(name="FactoryWorker", type=FactoryWorker.class)
    })
    private Employee employee;
    public void setEmployee(Employee val) {this.employee = val;}
}

将输出：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Department>
    <FactoryWorker>
        <id>999</id>
        <worksNights>true</worksNights>
    </FactoryWorker>
</Department>

演示：http://ideone.com/Gw07mI

JAXB编组子类继承

1 个答案: