Question

我有以下查询来显示某段时间内的销售情况，但不幸的是，它似乎没有报告在其他类别中购买过的客户。

例如，客户之前从未购买过产品（第2只或第3只猫），并且第一次购买5/5的产品。该报告没有出现在报告上，因为他们之前从cat 60购买了一些东西。

select CUSTOMER_DEL_HIST.CUSTOMER_NUMBER
      ,max ( CUSTOMER_DEL_HIST.SERVE_LOCATION) as SERVE_LOCATION
      ,max ( CUSTOMER_DEL_HIST.PRODUCT_NUMBER) as PRODUCT_NUMBER
      ,max ( CUSTOMER_DEL_HIST.DEL_DATE) as DEL_DATE
      ,max ( ORDER_RTE_BAL.WAREHOUSE) as WAREHOUSE
      ,max ( ORDER_RTE_BAL.ROUTE_NUMBER) as ROUTE_NUMBER
      ,max ( ORDER_RTE_BAL.ROUTE_DAY) as ROUTE_DAY
from CUSTOMER_DEL_HIST
        inner join INV_MASTER on CUSTOMER_DEL_HIST.PRODUCT_NUMBER = INV_MASTER.PRODUCT_NUMBER
        inner join ORDER_HEADER on CUSTOMER_DEL_HIST.ORDER_NUMBER = ORDER_HEADER.ORDER_NUMBER
        inner join ORDER_RTE_BAL
            on   ORDER_HEADER.WAREHOUSE_NUMBER = ORDER_RTE_BAL.WAREHOUSE
                and ORDER_HEADER.ROUTE_NUMBER = ORDER_RTE_BAL.ROUTE_NUMBER
                and ORDER_HEADER.ROUTE_DAY = ORDER_RTE_BAL.ROUTE_DAY
                and ORDER_HEADER.DELIVERY_DATE = ORDER_RTE_BAL.ROUTE_DATE
where    (CUSTOMER_DEL_HIST.DEL_DATE between X and Y)
        and (INV_MASTER.INVENTORY_CATEGORY in ('02', '03', '60', '74'))
        and (CUSTOMER_DEL_HIST.CUSTOMER_NUMBER not in 
            (select H2.CUSTOMER_NUMBER
            from CUSTOMER_DEL_HIST H2
            inner join INV_MASTER as I on H2.PRODUCT_NUMBER = I.PRODUCT_NUMBER
            where H2.DEL_DATE between '6/01/2014'   and '04/30/2015'
                and I.INVENTORY_CATEGORY in ('02', '03', '60', '74')))
group by CUSTOMER_DEL_HIST.CUSTOMER_NUMBER

我是SQL的新手但知道我应该在SELECT中使用union，但这就是它。不幸的是，我不够精通，所以我正在寻找一些帮助，以便我如何获得我想要的结果。

Answer 1

无法提供太多帮助解决实际问题的方法，但既然你说你是新手，我想我会告诉你，只需要一点点努力，你的查询就会更清晰。如果你开始使用别名，你可以消除每行数十个字符，你的代码可以更清洁。许多格式是个人偏好，但您发布的代码只是挑战阅读的方式。这是一种利用别名并大大清理它的方法。

SELECT cdh.customer_number
    , Max(cdh.serve_location) AS serve_location
    , Max(cdh.product_number) AS product_number
    , Max(cdh.del_date) AS del_date
    , Max(orb.warehouse) AS warehouse
    , Max(orb.route_number) AS route_number
    , Max(orb.route_day) AS route_day
FROM customer_del_hist cdh
INNER JOIN inv_master im ON cdh.product_number = im.product_number
INNER JOIN order_header oh ON cdh.order_number = oh.order_number
INNER JOIN order_rte_bal orb ON oh.warehouse_number = orb.warehouse
      AND oh.route_number = orb.route_number
      AND oh.route_day = orb.route_day
      AND oh.delivery_date = orb.route_date
WHERE cdh.del_date BETWEEN @StartDate AND @EndDate
    AND im.inventory_category IN ('02', '03', '60', '74')
    AND cdh.customer_number NOT IN 
    (
        SELECT h2.customer_number
        FROM customer_del_hist AS h2
        INNER JOIN inv_master AS i ON h2.product_number = i.product_number
        WHERE h2.del_date BETWEEN '6/01/2014' AND '04/30/2015'
            AND i.inventory_category IN ('02', '03', '60', '74') 
    ) 
GROUP  BY cdh.customer_number

Answer 2

在查询的where子句中，最后一个部分有

cdh.customer_number NOT IN 
    (
        SELECT h2.customer_number
        FROM customer_del_hist AS h2
        INNER JOIN inv_master AS i ON h2.product_number = i.product_number
        WHERE h2.del_date BETWEEN '6/01/2014' AND '04/30/2015'
            AND i.inventory_category IN ('02', '03', '60', '74') 
    )

这将是排除客户的区域。您可以看到子查询有一个where子句，并且此where子句指定inventory_category必须是02,03,60,74中的一个。因此，您找到所有购买任何一个类别中任何一个的客户，然后将它们从主查询的结果中排除。

SQL联合现有查询

2 个答案: