Question

我想多次运行一个脚本，使用不同的路径作为参数，并查看输出。

如果我在命令提示符

中运行带有参数path/lizard的脚本path_to_code/code1.cpp

path/lizard path_to_code/code1.cpp

我得到输出 - 我想在多个文件上运行此脚本。

查看this和类似问题，我试过了

import os, glob

def run_command(command):
    os.system(command)    

program = '"C:/Python27/Scripts/lizard.bat "'
path = '"path_to_code/*.cpp"'
for path1 in glob.glob(path):
    command = program + path1
    run_command(command)

没有输出。

import glob, subprocess

def run_command(command):
    p = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
    out, err = p.communicate()
    print out

program = '"C:/Python27/Scripts/lizard.bat "'
path = '"path_to_code/*.cpp"'
for path1 in glob.glob(path):
    command = program + path1
    run_command(command)

没有输出。

（当然我想通过目录递归迭代，但这是下一步）。

如何从脚本中获取程序的输出？我认为逻辑上两个版本都应该让我得到输出......我做错了什么？

Answer 1

尝试使用subprocess.check_output

它应该做你想要的。

[~] cat foo.sh
#!/bin/sh

echo "Hello World!"

[~] python2.7
Python 2.7.6 (default, Sep  9 2014, 15:04:36)
[GCC 4.2.1 Compatible Apple LLVM 6.0 (clang-600.0.39)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import subprocess
>>> foo = subprocess.check_output('./foo.sh')
>>> foo
'Hello World!\n'
>>>

所以在你的具体例子中

def run_command(command):
    return subprocess.check_output(command,stderr=subprocess.STDOUT)

Answer 2

从我看到的你忘了打电话沟通的过程。尝试

def run_command(command):
    p = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
    stdout, stderr = p.communicate()
    return iter(stdout, b'')

请参阅https://docs.python.org/2/library/subprocess.html?highlight=popen.communicate#subprocess.Popen.communicate

干杯

Answer 3

根据我的问题的评论，我试过

program = 'C:/Python27/Scripts/lizard.bat'
...
command = [program, path1]

工作 - 然后我意识到报价是问题，Etan Reisner是正确的。消除它们使它成功。

完整更正的代码：

import os, subprocess, fnmatch

def run_command(command):
    p = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
    out, err = p.communicate()
    print out

program = 'C:/Python27/Scripts/lizard.bat'
path = 'path_to_code'
matches = []
for root, dirs, filenames in os.walk(path):
    for filename in fnmatch.filter(filenames, '*.cpp'):
         matches.append(os.path.join(root, filename))

for path1 in matches:
    command = [program, path1]
    run_command(command)

无法从python运行shell脚本的输出

3 个答案: