关于组合的问题

时间:2010-06-13 07:32:14

标签: combinatorics

这是任务

How many ways are there to choose from the set {1, 2, . . . , 100} three distinct
numbers so that their sum is even?

首先,即使只有

,三个数字之和也是如此
1.all number is even
2.two of them is odd and one is even

我知道

(n)   =  n!/(k!*(n-k)!   
(k)   

任何人都可以帮我解决这个问题

1 个答案:

答案 0 :(得分:1)

那不就是

(50 choose 3) + (50 choose 2) * (50 choose 1)

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