Question

我有Flask API都使用phone作为可选的url参数，如下所示，我想使用装饰器来验证电话号码是否正确。那么我可以得到参数＆＃34; phone＆＃34;某个地方没有解析请求网址？

@user_api.route("/<phone>/login")
@check_phone
def login(phone):
    f = OrderedDict()
    f['error'] = 0
    return jsonify(f)

@user_api.route("/<phone>/logout")
@check_phone
def logout(phone):
    f = OrderedDict()
    f['error'] = 0
    return jsonify(f)

Answer 1

有一种更好的机制来验证内置于Werkzeug（和Flask）的url值。定义converter并像使用路径中的任何其他转换器一样使用它（例如，<int:id>）。

from werkzeug.routing import BaseConverter, ValidationError

class PhoneConverter(BaseConverter):
    regex = r'\d{7,10}'  # this validates the basic form of the value

    def to_python(self, value):
        # do more complicated validation
        if not complicated_phone_validation(value):
            raise ValidationError('not a valid phone number')

        return value

app.url_map.converters['phone'] = PhoneConverter

@app.route('/<phone:phone>')
def get_phone(phone):
    # phone is valid

您还可以使用before_request函数验证所有带手机参数的路线，而无需全部装饰。

from flask import request, abort

@app.before_request
def valid_phone():
    if 'phone' not in request.view_args:
        return  # view has no phone arg

    if not complicated_phone_validation(request.view_args['phone']):
        abort(404)

@app.route('/<phone>')
def get_phone(phone):
    # phone is valid

@app.route('/<other>')
def get_other(other):
    # no phone arg, no validation

如果你真的想使用装饰器，可以使用参数调用装饰函数。

from functools import wraps

def check_phone(f):
    @wraps(f)
    def inner(**kwargs):
        phone = kwargs['phone']
        # do some validation
        return f(**kwargs)

    return inner

@app.route('/<phone>')
@check_phone
def get_phone(phone):
    # phone is valid

如何在装饰器中获取Flask可选URL参数？

1 个答案: