Question

我有一个名为Messages的Parse.com类，其中我有3列：

- fromUser - Pointer<_User>
- toUser - Pointer<_User>

在我的UITableView中，我检索Messages-class中的所有对象，其中toUser等于PFUser currentUser。当我尝试为fromUser分配标签时，我收到此错误：

Terminating app due to uncaught exception 'NSInternalInconsistencyException', reason: 'Key "username" has no data.  Call fetchIfNeeded before getting its value.

以下是我查询的方式：

- (void)retriveMessages {
    PFQuery *query = [PFQuery queryWithClassName:@"Messages"];
    [query whereKey:@"toUser" equalTo:[PFUser currentUser]];
    [query orderByDescending:@"createdAt"];
    query.limit = 1000;
    [query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
        if (error) {
            NSLog(@"Error: %@ %@", error, error.userInfo);
        } else {

            // Found messages!
            self.messages = objects;
            [self.tableView reloadData];
            [_message fetchIfNeeded];
            NSLog(@"Retrived %d messages", self.messages.count);
        }
    }];
}

这就是我尝试将标签分配给fromUser-row的方式，这是一个指向User类的指针：

-(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {

    MessageCell *cell = [tableView dequeueReusableCellWithIdentifier:@"MessageCell" forIndexPath:indexPath];

    _message = [_messages objectAtIndex:indexPath.row];

    [_message fetchIfNeeded];

    PFUser *user = (PFUser*)[_message objectForKey:@"fromUser"];
    NSString *nameString = [user username];
    cell.nameLabel.text = nameString;

    cell.feedDelegate = self;

    return cell;
}

Answer 1

为了访问指向@＆＃34; fromUser＆＃34;的属性，你必须在find中急切地获取它。将其添加到查询中：

[query includeKey:@"fromUser"];

从PFUser中提取用户详细信息不起作用：键＆＃34;用户名＆＃34;没有数据

1 个答案: