Question

我有这个，如果自动售货机的代码，我觉得它可以缩短，任何想法？

Potato_size = raw_input(“Would you like a small, medium or large potato?”)
if Potato_size == “Small”:
    print “The price is £1.50 without toppings, continue?”
elif Potato_size == “Medium”:
    print “The price is £2.00 without toppings, continue?”
elif Potato_size == “Large”:
    print “The price is £2.50 without toppings, continue?”
else:
    print “Please answer Small, Medium or Large.”

由于

Answer 1

那应删除if/elif条款

Potato_size = raw_input("Would you like a small, medium or large potato?")

Sizes={"Small":"£1.50","Medium":"£2.00","Large":"£2.50"}
try:
   print "The price is {} without toppings, continue?".format(Sizes[str(Potato_size)])
except NameError:
    print "Please answer Small, Medium or Large."

Answer 2

不是最好的，但它发布的时间最短。

sizes={"SMALL":"£1.50","MEDIUM":"£2.00","LARGE":"£2.50"}
price_str = {k: "The price is {} without toppings, continue?".format(v)
                 for k, v in sizes.iteritems()}

potato_size = raw_input("Would you like a small, medium or large potato?  ")
print price_str.get(potato_size.upper(), "Please answer Small, Medium or Large.\n")

Answer 3

你可以用dict来缩短它，

potato_size ={
    "small": “The price is £1.50 without toppings, continue?”
    "medium":“The price is £2.00 without toppings, continue?”
    "large" :“The price is £2.50 without toppings, continue?”
}
user_input =  raw_input(“Would you like a small, medium or large potato?”)
if user_input in potato_size :
    print potato_size[user_input]
else:
    print “Please answer Small, Medium or Large.”

如何缩短这个if / elif python代码？

3 个答案: