Question

我在tinyMCE的工具栏中添加了一个按钮来启动弹出窗口。按钮调用editor.windowManager.open(...)并传递此类参数作为URL：

/wp-admin/media-upload.php?post_id=SOME_POST_ID&type=z_recipe&tab=amd_zlrecipe&TB_iframe=true

在我的主插件文件中，我有这段代码在调用上述URL时生成一些iframe代码：

if (strpos($_SERVER['REQUEST_URI'], 'media-upload.php') && strpos($_SERVER['REQUEST_URI'], '&type=z_recipe') && !strpos($_SERVER['REQUEST_URI'], '&wrt='))
{
    ZipRecipes::zrdn_iframe_content($_POST, $_REQUEST);
    exit;
}

我发现a related answer about media uploads声称以下内容应该有效：

<!DOCTYPE html>
<!--suppress HtmlUnknownTarget -->
<head>
    <?php


    function load_custom_code() {
        // jQuery
        wp_enqueue_script('jquery');
        // This will enqueue the Media Uploader script
        wp_enqueue_media();
    }
    add_action( 'admin_enqueue_scripts', 'load_custom_code' );
    ?>

</head>
<body id="amd-zlrecipe-uploader">
    <label for="image_url">Image</label>
    <input type="text" name="image_url" id="image_url" class="regular-text">
    <input type="button" name="upload-btn" id="upload-btn" class="button-secondary" value="Upload Image">

    <script type="text/javascript">
        jQuery(document).ready(function($){
            $('#upload-btn').click(function(e) {
                e.preventDefault();
                var image = wp.media({
                    title: 'Upload Image',
                    // mutiple: true if you want to upload multiple files at once
                    multiple: false
                }).open()
                    .on('select', function(e){
                        // This will return the selected image from the Media Uploader, the result is an object
                        var uploaded_image = image.state().get('selection').first();
                        // We convert uploaded_image to a JSON object to make accessing it easier
                        // Output to the console uploaded_image
                        console.log(uploaded_image);
                        var image_url = uploaded_image.toJSON().url;
                        // Let's assign the url value to the input field
                        $('#image_url').val(image_url);
                    });
            });
        });
    </script>
</body>

但是，浏览器开发工具告诉我jQuery和$未定义。

所以，这可以通过修复jQuery和wp_enqueue_media的方式或者改变我的初始弹出窗口的创建方式来解决。

你有任何帮助，我可以使用。

从另一个弹出窗口中启动WordPress中的媒体上传器

0 个答案: