D3js在圆圈上找到最近点

时间:2015-05-29 13:55:57

标签: javascript d3.js pi sin

我想要实现的是获取mousemove事件的当前坐标,并将它们与圆上最近位置的坐标相匹配。我已经设法使用for循环来部分工作,它循环遍历圆中的每个可能的点并比较坐标以找到最近的点:

        for (var i = Math.PI; i > -Math.PI; i -= 0.01) {

            // coords of current point in circle:

            var curX = Math.sin(i+Math.PI / 2)*radius + 200,
            curY = Math.sin(i)*radius + 200;

            // conditional which attempts to find the coords of the point closest to the cursor...

                if (Math.abs((x - curX)) < distanceX && Math.abs((y - curY)) < distanceY ) {
                    distanceX = Math.abs((x - curX));
                    distanceY = Math.abs((y - curY));

                    // and then assigns the values to the newX/newY variables

                    newX = curX;
                    newY = curY;
                }

            }
问题是这个解决方案通常会返回错误的坐标,我不知道为什么。

jsfiddle看看我的意思:

https://jsfiddle.net/eLn4jsue/

1 个答案:

答案 0 :(得分:4)

无需循环,只需计算圆心和圆上鼠标之间的点。

var dx = x - 200,
    dy = y - 200,
    dist = Math.sqrt(dx*dx + dy*dy),
    newX = 200 + dx * radius / dist,
    newY = 200 + dy * radius / dist;

https://jsfiddle.net/3n0dv5v8/1/