Question

我有一项任务是向来自C网站的请求发送JSON响应。我无法以正确的格式格式化响应。

基本上这是一个过程：用户点击网站上的“StopAll”按钮，我需要将所有设备的数据发回，作为一切已成功完成的响应。我知道原始数据和格式应该是什么样的......但我无法将其转换为“C”......

数据：

更新所有请求：

{powerStates: [true, false], startStates: [false, false], temperatures: [30, 40], macAddresses: ['11', '22'], status_code: 1}

我试过的代码：

if (client) {
    Serial.println ("new client");
    // An http request ends with a blank line
    boolean currentLineIsBlank = true;
    while (client.connected ()) {
      if (client.available ()) {
        char c = client.read ();
        buffer + = c;
        Serial.write (c);

        // If you've gotten to the end of the line (received a newline
        // Character) and the line is blank, the http request has ended,
        // So you can send a reply

          if (buffer.indexOf ("true")> = 0 || buffer.indexOf ("false")> = 0) {

          // You're starting a new line

          client.println ("HTTP / 1.1 200 OK");
          client.println ("Content-Type: application / json");
          //client.println ();
          client.println ("{\" powerStates \ ": [\" true \ ", \" true \ ", \" true \ "], \" startStates \ ": [\" false \ ", \" false \ " , \ "false \"], \ "temperatures \": [\ "444 \", \ "22 \", \ "33 \"], \ "macAddresses \": [\ "11-22-33-34 \ ", \" 11-22-33-35 \ ", \" 11-22-34-37 \ "], \" status_code \ ": 1}");
          client.println ();

以上是响应代码.....但它不会更改网站上的任何数据。所以我不确定这个回复是否会进入网络。

有找到方法吗？

Answer 1

如果只输出一个简单的JSON，则可以避免使用JSON库，只需使用printf即可。

#include <stdio.h>
#include <stdlib.h>


// Output simple fixed JSON data.
int main(int argc, char* *argv)
{
    // Simulate your data as simply as possible
    bool powerStates[2];
    bool startStates[2];
    int temperatures[2];
    int macAddresses[2];
    int status_code;


    // Set your data
    powerStates[0] = true;
    powerStates[1] = false;
    startStates[0] = false;
    startStates[1] = false;
    temperatures[0] = 30;
    temperatures[1] = 40;
    macAddresses[0] = 11;
    macAddresses[1] = 22;
    status_code = 1;


    // Output JSON very simply
    printf("{powerStates: [%s, %s], startStates: [%s, %s], temperatures: [%d, %d], macAddresses: ['%d', '%d'], status_code: %d}",
           powerStates[0]?"true":"false",
           powerStates[1]?"true":"false",
           startStates[0]?"true":"false",
           startStates[1]?"true":"false",
           temperatures[0],
           temperatures[1],
           macAddresses[0],
           macAddresses[1],
           status_code = 1);

    return 0;
}

如果您需要字符串而不是输出，只需更改为sprintf即可。

C中的JSON响应格式

1 个答案: