如何分离音频的频率

Question

我只想确定.mp3或.wav文件的频率并将其打印

import pyaudio
import wave
import numpy as np

chunk = 2048
wf = wave.open('/home/pi/Adhuri.wav', 'rb')
swidth = wf.getsampwidth()
RATE = wf.getframerate()
window = np.blackman(chunk)
p = pyaudio.PyAudio()
stream = p.open(format =
            p.get_format_from_width(wf.getsampwidth()),
            channels = wf.getnchannels(),
            rate = RATE,
            output = True)

# read some data
data = wf.readframes(chunk)
# play stream and find the frequency of each chunk
while len(data) == chunk*swidth:
    print "ok"
    stream.write(data)
    indata = np.array(wave.struct.unpack("%dh"%(len(data)/swidth),\
                                     data))*window
    fftData=abs(np.fft.rfft(indata))**2
    which = fftData[1:].argmax() + 1
    if which != len(fftData)-1:
        y0,y1,y2 = np.log(fftData[which-1:which+2:])
        x1 = (y2 - y0) * .5 / (2 * y1 - y2 - y0)
        thefreq = (which+x1)*RATE/chunk
        print "The freq is %f Hz." % (thefreq)
    else:
        thefreq = which*RATE/chunk
        print "The freq is %f Hz." % (thefreq)
    # read some more data
    data = wf.readframes(chunk)
if data:
    stream.write(data)
stream.close()
p.terminate()

它不满足而len（数据）== chunk swidth：当我写的时候len（数据）！= chunk swidth：只有这样它才进入循环并显示错误信息valueerror：操作数不能与形状一起广播（4096）（2048）。如何解决这个问题？