Question

我将以下数据存储在文件中：

number1:0 number2=1 minnumber2number3:1 minnumber3:0 minnumber4:0 maxnumber2number3:1 maxnumber3:0 maxnumber4:0 no. of number5 per bucket:35 num:
number1:0 number2=0 minnumber2number3:3 minnumber3:3 minnumber4:11577215 maxnumber2number3:3 maxnumber3:3 maxnumber4:14707215 no. of number5 per bucket:6 num:
number1:0 number2=1 minnumber2number3:1 minnumber3:0 minnumber4:0 maxnumber2number3:3 maxnumber3:1 maxnumber4:1882188 no. of number5 per bucket:8 num:
number1:0 number2=1 minnumber2number3:2 minnumber3:248 minnumber4:10000000 maxnumber2number3:2 maxnumber3:248 maxnumber4:10000000 no. of number5 per bucket:91 num:
number1:0 number2=1 minnumber2number3:2 minnumber3:239 minnumber4:11641499 maxnumber2number3:2 maxnumber3:244 maxnumber4:2248700 no. of number5 per bucket:8999 num:
number1:0 number2=1 minnumber2number3:2 minnumber3:251 minnumber4:2000000 maxnumber2number3:2 maxnumber3:251 maxnumber4:2000000 no. of number5 per bucket:8986 num:
number1:0 number2=1 minnumber2number3:2 minnumber3:232 minnumber4:14775115 maxnumber2number3:1 maxnumber3:0 maxnumber4:0 no. of number5 per bucket:6385 num:
number1:0 number2=1 minnumber2number3:2 minnumber3:253 minnumber4:9404695 maxnumber2number3:1 maxnumber3:0 maxnumber4:0 no. of number5 per bucket:8863 num:
number1:0 number2=1 minnumber2number3:3 minnumber3:3 minnumber4:14777215 maxnumber2number3:1 maxnumber3:0 maxnumber4:0 no. of number5 per bucket:2679 num:

现在我需要在“每桶数量为5号”之后检索所有数字并将它们相加。例如，我需要总结以下内容：

我知道我可以使用像python这样的编程语言来做同样的事情，但我正在学习linux命令是否有像grep这样的linux命令，这可以帮助我做同样的事情。

Answer 1

如果您对按列号选择列感到满意：

tr ":" " " <table | awk '{print $21}'

假设您的数据位于文件table中，则第一个命令将:转换为空格，第二个命令转到第21列。

编辑：纯awk，指定字段分隔符。

awk 'BEGIN{FS="[ :]"} {print $21}' table

第二次编辑：选择grep并与awk求和：

grep -oE "no\. of number5 per bucket:[^ ]*" table | awk 'BEGIN{FS=":"} {S+=$2} END{print S}'

第3次编辑：在阅读了Anton的解决方案后，我被提醒，您还可以使用sed来匹配名称并获取组中的解决方案（\1）

sed -rn 's/^.*no\. of number5 per bucket:([0-9]*).*/\1/p' table | awk '{S+=$1} END {print S}'

Answer 2

您可以尝试使用sed：

sed -e 's/^.*bucket://' | sed -e 's/[a-zA-Z]*:$//'

Answer 3

一个简单的bash脚本也可以：

#!/bin/bash

declare -i sum=0

while read -r line; do 
    n=${line##*number5 per bucket:}
    sum+=$((${n% num:}))
done <"$1"

printf "\n the sum is: %d\n\n" $sum

<强>输出

$ bash script.sh filename

 the sum is: 36052

在字符串后汇总数字

3 个答案: