ng-options返回对象而不是实际选项值

时间:2015-06-06 20:53:50

标签: angularjs

我有一个对象数组:

$scope.allCategories = [{'name': 'cat1', 'description: ... },
                        {'name': 'cat2', 'description: ... }, 
                        {...}];

我之前使用过:

<select ng-model="mycategory" ng-change="test()">
    <option ng-repeat="category in allCategories">{{ category.name }}</option>
</select>

哪种方法很好,但它不是“Angular方式”。所以我把它改成了:

<select ng-model="mycategory" ng-change="test()" ng-options="category.name for category in allCategories track by category.name"></select>

构建这个正确的html:

<select ...>
<option value="cat1" label="cat1">cat1</option>
<option value="cat2" label="cat2">cat2</option>
...
</select>

但是在test()

// called whenever select changes
$scope.test = function() {
    console.log($scope.mycategory);   
}

$scope.mycategory打印出对象{'name': 'cat1', 'description: ... }而不是字符串值。使用ng-repeat的先前版本会给我字符串值,所以这让我失望了。

有没有办法在$scope.mycategory = $scope.mycategory['name'];内没有test()的情况下自动获取字符串值?

2 个答案:

答案 0 :(得分:1)

这是代码:

<select ng-model="correctlySelected"
    ng-options="category.name as category.name for category in allCategories">
</select>

答案 1 :(得分:0)

要获得精确选择的值,请更改您的测试方法,如下所示:

$scope.test = function() {
console.log($scope.mycategory);}

将您的html部分更改为

<select ng-model="mycategory" ng-change="test()" ng-options="category.name for category in allCategories"></select>
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