Question

我试图实现一个修改字符串的函数：

代码如下：

test.h文件：

#ifndef header_file
#define header_file

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

char * findWord(char *, char *);

#endif

test.c文件：

#include"test.h"

char * findWord(char *array, char *action)
{
    char testchar;
    int count=0, i=0, j, start = 0, end, wordLength = 0, charCount =0, k=0;
    char *temp = malloc(sizeof(char)*400);
    char *word = malloc(sizeof(char)*30);
    char *replaceString = malloc(sizeof(char)*80);

    if(strcmp(action,"replace") == 0)
    {
        while((testchar = array[i]) != '\0')
                {

            if(testchar == ',')
            {
                start = i+1;
                i++;
                continue;
            }
            else if(testchar == ':')
            {
                 end = i;
                 word[charCount] = '\0';
                 charCount = 0;
                 printf("Start is: %d \n", start);

                 for(j=0; j< strlen(array); j++)
                 {
                    if(j == start)
                    {
                        sprintf(replaceString, "%s%s%s", "replace_",word,"_ii");
                        printf("Replace String for word %s is %s.\n",word,replaceString);
                        strcat(temp,replaceString);
                        j = (j-1)+(strlen(word));
                        k= strlen(replaceString);

                        printf("The value of J is %d for word %s.\n",j,word);
                    }
                    else
                    {
                        temp[k++] = array[j];
                    }
                 }
                 temp[k] = '\0';
                 k=0;

                printf(" Words %s is replaced. The new string is:\n", word);
                printf("%s\n",temp);
                memset(word,'0',30);
                memset(temp,'0',400);
                memset(replaceString,'0',80);
                i++;
                continue;
            }

            if(testchar != 'Y')
            {
                word[charCount] = testchar;
                charCount++;
            }

            i++;
        }
    }

    else if(strcmp(action,"MISSING") == 0)
    {

    }
    else if(strcmp(action,"EMPTY") == 0)
    {

    }
    else
        printf("Something went wrong.\n");

   free(temp);
   free(word);
   free(replaceString);
}

main.c文件：

#include"test.h"

int main()
{
    char sc[] = "cn:Y,x509UniqueIdentifier:Y,pseudonym:Y,name:Y,l:Y,street:Y,state:Y,postalAddress:Y,postalCode:Y,telephoneNumber:Y,emailAddress:Y";
    findWord(sc, "replace");

    return 0;
}

预期输出为：

Replace String for word cn is replace_cn_ii.
replace_cn_ii:Y,x509UniqueIdentifier:Y,pseudonym:Y,name:Y,l:Y,street:Y,state:Y,postalAddress:Y,postalCode:Y,telephoneNumber:Y,emailAddress:Y

。。。 10输出。

但由于strlen()的意外行为，它给出了垃圾值。 strcat()函数后的单词值会自动更改我哪里错了？让我知道这个问题以及如何解决它。

谢谢！

Answer 1

您在strcat()上呼叫temp，但temp不包含有效字符串。这给出了未定义的行为。

您必须首先确保temp有效，即将其设为空字符串：

*temp = '\0';

当然，您还必须确保分配成功。

strlen函数的意外输出

1 个答案: