Question

我有一个问题：

SELECT CAST(SUBMITDATE as date) as 'Date'

,COUNT(*) as [Tickets Submitted]
,SUM(CASE WHEN STATUS = 'Closed' THEN 1 ELSE 0 END) as [Tickets Closed]

FROM Table1

    WHERE SUBMITDATE >= '2015-05-29'
      AND SUBMITDATE < '2015-06-03'


GROUP BY CAST(SUBMITDATE as date)

产生以下结果：

Date        Tickets Submitted   Tickets Closed
2015-05-29  1062                1040
2015-05-30  429                 416
2015-05-31  260                 250
2015-06-01  705                 654
2015-06-02  556                 515
2015-06-03  508                 452

我想计算已关闭的门票百分比。 [门票关闭]除以[提交门票]。

当我尝试添加：,SUM((CASE WHEN STATUS = 'Closed' THEN 1 ELSE 0 END)/COUNT(*)) as [Percentage of Tickets Closed]

时

我收到以下错误：

＆＃34;无法对包含聚合或子查询的表达式执行聚合函数。＆＃34;

有人可以帮忙吗？

非常感谢。

Answer 1

不要将COUNT放在SUM中。试试这样：

,CAST(SUM(CASE WHEN mrSTATUS = 'Closed' THEN 1 ELSE 0 END) AS float)/CAST(COUNT(*) AS float) as [Percentage of Tickets Closed]

SUM和COUNT函数将产生整数，这意味着除法也将产生整数。将它们作为花车进行铸造以获得分数。

Answer 2

,CAST(CAST(SUM(CASE WHEN STATUS = 'Closed' THEN 1 ELSE 0 END) as FLOAT)/CAST(COUNT(*) as FLOAT)*100 as DECIMAL(5,2)) as [% of Tickets Closed]

是我正在寻找的。

以下是我得到的结果：

Date        Tickets Submitted   Tickets Closed  % of Tickets Closed
2015-05-29  1062                1047            98.59
2015-05-30  428                 418             97.66
2015-05-31  260                 253             97.31
2015-06-01  703                 669             95.16
2015-06-02  555                 517             93.15
2015-06-03  507                 463             91.32

如何计算一列到另一列的百分比？

2 个答案: