查询基于密钥和记录的记录MAX日期栏

时间:2015-06-09 20:51:54

标签: tsql sql-server-2012

我希望我能就如何最有效地处理正确有效的数据集做一些澄清。

以下是我正在使用的三个不同表格中的三个查询。 Donor_ID是表之间的关键,但正如您所看到的 - 每个Donor_ID都有多个记录关联 - runid_gmt列具有不同的日期。

理想情况下,我想为每条记录使用max(runid_gmt) - 并加入Donor_ID上的EMAIL和ADDRESSES表,但也只选择每个表中的max(runid_gmt)记录。

我相信这是我需要做的 - 但不确定。关于如何解决这个问题的任何建议?

SELECT donor_id, last_name, birthdate, runid_gmt FROM [dbo].TBL_DONORS where donor_id = '51999441' order by runid_gmt desc;

Donors

SELECT donor_id, city, state, zip, runid_gmt FROM [dbo].TBL_ADDRESSES where donor_id = '51999441' order by runid_gmt desc;

Addresses

SELECT donor_id, donor_email, runid_gmt FROM [dbo].TBL_EMAIL where donor_id = '51999441' order by runid_gmt desc;

Email

1 个答案:

答案 0 :(得分:1)

尝试row_number窗口功能:

select * from
(select *, row_number() over(partition by donorid order by gmt desc) rn 
 from donors) t1 join

(select *, row_number() over(partition by donorid order by gmt desc) rn 
 from addresses) t2 on t1.donorid = t2.donorid join

(select *, row_number() over(partition by donorid order by gmt desc) rn 
 from emails) t3 on t1.donorid = t3.donorid
where t1.rn = 1 and t2.rn = 1 and t3.rn = 1
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