如何从JOptionPane中的String数组中选择索引值

时间:2010-06-19 05:30:39

标签: java joptionpane

我创建了一个JOptionPane作为选择方法。我想要字符串数组的选择1,2或3的int值,所以我可以将它用作计数器。如何获取数组的索引并将其设置为等于我的int变量loanChoice?

public class SelectLoanChoices {
    int loanChoice = 0;
    String[] choices = {"7 years at 5.35%", "15 years at 5.5%",
            "30 years at 5.75%"};
        String input = (String) javax.swing.JOptionPane.showInputDialog(null, "Select a Loan"
                ,"Mortgage Options",JOptionPane.QUESTION_MESSAGE, null,
                choices,
                choices[0]
                **loanChoice =**);
}

2 个答案:

答案 0 :(得分:1)

如果要返回选项的索引,可以使用JOptionPane.showOptionDialog()。否则,您将必须遍历选项数组以根据用户选择查找索引。

例如:

public class SelectLoanChoices {
 public static void main(final String[] args) {
  final String[] choices = { "7 years at 5.35%", "15 years at 5.5%", "30 years at 5.75%" };
  final Object choice = JOptionPane.showInputDialog(null, "Select a Loan", "Mortgage Options",
    JOptionPane.QUESTION_MESSAGE, null, choices, choices[0]);
  System.out.println(getChoiceIndex(choice, choices));

 }

 public static int getChoiceIndex(final Object choice, final Object[] choices) {
  if (choice != null) {
   for (int i = 0; i < choices.length; i++) {
    if (choice.equals(choices[i])) {
     return i;
    }
   }
  }
  return -1;
 }
}

答案 1 :(得分:1)

由于蒂姆·本德已经给出了一个冗长的答案,这里是一个紧凑的版本。

int loanChoice = -1;
if (input != null) while (choices[++loanChoice] != input);

另外,请注意showInputDialog(..)采用对象数组,而不是字符串。如果您有贷款对象并实施了他们的toString()方法来说“X年在Y.YY%”,那么您可以提供一系列贷款,然后可能跳过数组索引并直接跳到选定的贷款。 / p>