Question

我有一个包含3列的表格：

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此表中有很多数据。并非所有日历日期都显示在表格中。如何找到日期差距大于Date smalldatetime not null Val1 decimal not null Val2 decimal not null天的所有地方？

Answer 1

以下是如何执行此操作的方法：

DECLARE @t TABLE
    (
      Date SMALLDATETIME NOT NULL ,
      Val1 DECIMAL NOT NULL ,
      Val2 DECIMAL NOT NULL
    )

INSERT INTO @t VALUES
('20150101', 1, 1),
('20150104', 1, 1),
('20150109', 1, 1),
('20150201', 1, 1),
('20150305', 1, 1),
('20150506', 1, 1)


;WITH cte AS(SELECT *, ROW_NUMBER() OVER(ORDER BY Date) AS Rn FROM @t)
SELECT c2.*, c1.Date AS PrevDate FROM cte c1
JOIN cte c2 ON c1.Rn = c2.Rn - 1
WHERE DATEDIFF(d, c1.Date, c2.Date) > 30 --this is your X

输出：

Date                Val1    Val2    Rn  PrevDate
2015-03-05 00:00:00 1       1       5   2015-02-01 00:00:00
2015-05-06 00:00:00 1       1       6   2015-03-05 00:00:00

Answer 2

您可以在SQL Server数据库中创建日期表并使用SQL date table to find gaps in date

日期表是包含所有可能日期的参考表。您将比较目标表和日期列加入日期列并列出缺失的列表

找出日期的差距

2 个答案: