android两个线程有​​一个延迟

Question

我希望你能帮助我。我需要两个循环。它们必须同时运行，一个循环需要延迟。第一个循环必须在Array中创建ImageViews，第二个循环必须获取视图上的位置。我知道它必须用Threads创建但是如何？或者换一种方式呢？

public ImageView[] bubbles = new ImageView[];

public void create_bubbles() throws InterruptedException {


    RelativeLayout game_layout = (RelativeLayout) findViewById(R.id.game_layout){

        ThreadForLoopA threadA = new ThreadForLoopA();
        ThreadForLoopB threadB = new ThreadForLoopB();

        threadA.start();
        threadB.start();

    }

}

public class ThreadForLoopA extends Thread{

    float posX = 10;
    float posY = 10;

    @Override
    public void run(){

            for(int i=0;;i++){


        bubbles[i] = new ImageView(null);
        bubbles[i].setImageResource(R.drawable.unbenannt);
        game_layout.addView(bubbles[i], 100, 100);
        setPos(posX, posY, bubbles[i]);
        posX = posX + 100;

        if(i == 5){
            break;
        }

        }



    }
}


public class ThreadForLoopB extends Thread{

    @Override
    public void run(){
        for(int i = 0 ; ; i++){

            float location;
            location = bubbles[i].getY();
            if(i == 5){

                break;

            }

        }
    }
}

}

Answer 1

您可以从Handler发布延迟，但是对于您的情况，您必须在ThreadA完成后启动ThreadB，否则您将无法获得值。

延迟执行：

   RelativeLayout game_layout = (RelativeLayout) findViewById(R.id.game_layout){

    ThreadForLoopA threadA = new ThreadForLoopA();
    final ThreadForLoopB threadB = new ThreadForLoopB();

    threadA.start();
    new Handler().postDelayed(new Runnable(){
    public void run(){
         threadB.start();
    }}, 5000);//5 seconds

}