Question

我正在努力使用适当的逻辑来比较以下数组：

$a = [
    "ip" => [
        "1.2.3.4",
        "4.3.2.1",
    ],
    "domain" => [
        "example.com",
        "another.domain",
    ],

];

$b = [
    [
        "id"=> 136589,
        "metaname" => "ip",
        "metavalue" => "1.2.3.4",
    ],
    [
        "id"=> 136590,
        "metaname" => "domain",
        "metavalue" => "example.com",
    ],
];

我需要循环$a以查找'ip'中不存在的密钥（'1.2.3.4'）值（$b）组合。在数组$a中，我需要捕获ip '4.3.2.1'和域'another.domain'

$b可以使用不同的键匹配值吗？

一个很好的例子就是'ip'个地址。可能与IP相关的元名值为'ip'，'ip.dst'和'ip.src'。返回示例数据 - 即使'ip'匹配，如果元名称不匹配，也应该跳过它。

foreach ($a as $metaName => $metaValues)
{
    foreach ($metaValues as $metaValue)
    {
        foreach ($b as $row)
        {
            if (in_array($metaName, $row) && in_array($metaValue, $row))
            {
                # this pair exists, move on to next $metaName-$metaValue pair
                break;
            }
            # this is where i am now, making small progress
            # more trial and error going on
        }
    }
}

在我的示例代码中，评论是我需要帮助的地方。我已经尝试了不同的检查和循环的各种迭代来捕获适当的数据无济于事......

in_array($metaValue, $row)
array_keys($row, $metaValue)

结合各种if语句等等，但这无济于事。

如果我的描述未能明确，则下表可能会有所帮助。

+ A ---------------------+----+ B ------------------+ Comment ------------------------+
| ip, 1.2.3.4            | == | ip, 1.2.3.4         | Skip, no more checks            |
+------------------------+----+---------------------+---------------------------------+
| ip, 4.3.2.1            | != | ip, 1.2.3.4         | Keep checking                   |
|                        | != | domain, example.com | No more B to compare, I want A! |
+------------------------+----+---------------------+---------------------------------+
| domain, example.com    | != | ip, 1.2.3.4         | Keep checking                   |
|                        | == | domain, example.com | Skip, no more checks            |
+------------------------+----+---------------------+---------------------------------+
| domain, another.domain | != | ip, 1.2.3.4         | Keep checking                   |
|                        | != | domain, example.com | No more B to compare, I want A! | 
+------------------------+----+---------------------+---------------------------------+

Answer 1

只需稍加修改并使用reference即可。但要小心第一个foreach，第一个参数是$metaname，但第二个参数不是$metavalue，你需要第二个foreach循环它们：

foreach ($a as $metaname => &$group) { // & is present to unset the original array
    foreach ($group as $i => $metavalue) { // here you get the distinct metavalues
        foreach ($b as $row) {
            if (!($row['metaname'] === $metaname)) {
                continue;
            }
            if ($row['metavalue'] === $metavalue) {
                unset($group[$i]);
            }
        }
    }
}

var_dump($a);

之后var_dump() $a

array(2) {
  ["ip"]=>
  array(1) {
    [1]=>
    string(7) "4.3.2.1"
  }
  ["domain"]=>
  &array(1) {
    [1]=>
    string(14) "another.domain"
  }
}

第一个foreach（）将访问$a数组的不同值，而$metavalue实际上是包含这些元数据的数组。

比较两个值的两个数组

1 个答案: