Question

我有一个输入文件，格式如下：

457526373620277249  17644162    Sat Apr 19 14:29:22 +0000 2014  0   nc  nc  U are expressing a wish not a fact ;) @Manicdj99 @ANTIVICTORIA @Nupe117 @cspanwj
457522541926842368  402127017   Sat Apr 19 14:14:09 +0000 2014  0   nc  nc  @dfwlibrarian You're a great one to call somebody else "educationally challenged!" I'd call that a name call. #YouLose #PJNET #TCOT #TGDNGO YouLose,PJNET,TCOT,TGDNGO
457519476511350786  65713724    Sat Apr 19 14:01:58 +0000 2014  0   nc  nc  @Manicdj99 @Nupe117 @cspanwj only some RW fringies are upset- &amp; they're ALWAYS angry at something-also too fat 2 get out of lazyboys

我需要根据时间对数据进行排序。我正在使用strptime函数，但无法根据时间对整个数据进行排序。

import datetime
dt=[]
for line in f:
    splits = line.split('\t')
    dt.append(datetime.datetime.strptime(splits[2], "%a %b %d %H:%M:%S +0000 %Y"))
    dt.sort()

Answer 1

您想要生成一个行列表，然后才对整个列表进行排序;您只捕获时间戳，并在每次添加新时间戳时对该列表进行排序，忽略其余数据。

您可以使用csv module：

更轻松地阅读数据

import csv
from datetime import datetime
from operator import itemgetter

rows = []
with open(yourfile, 'rb') as f:
    reader = csv.reader(f, delimiter='\t')
    for row in reader:
        row[2] = datetime.strptime(row[2], "%a %b %d %H:%M:%S +0000 %Y")
        rows.append(row)

rows.sort(key=itemgetter(2))  # sort by the datetime column

Answer 2

假设您的data.txt文件看起来像这样（我将其截断到右侧）：

457526373620277249 17644162 Sat Apr 19 14:29:22 +0000 2014 0 457522541926842368 402127017 Sat Apr 19 14:14:09 +0000 2014 0 457519476511350786 65713724 Sat Apr 19 14:01:58 +0000 2014 0

我还假设它的TAB分隔在这里。

这将正确解析数据，将日期转换为正确的datetime对象，然后使用sorted(iterable, key=)对其进行排序：

示例：

from __future__ import print_function from datetime import datetime from operator import itemgetter def map_to_datetime(xs, index, format="%a %b %d %H:%M:%S +0000 %Y"): for x in xs: x[index] = datetime.strptime(x[index], format) data = [line.split("\t") for line in map(str.strip, open("data.txt", "r"))] map_to_datetime(data, 2) for entry in sorted(data, key=itemgetter(2)): print(entry)

<强>输出：

$ python -i foo.py ['457519476511350786', '65713724', datetime.datetime(2014, 4, 19, 14, 1, 58), '0'] ['457522541926842368', '402127017', datetime.datetime(2014, 4, 19, 14, 14, 9), '0'] ['457526373620277249', '17644162', datetime.datetime(2014, 4, 19, 14, 29, 22), '0'] >>>

如何在python中根据日期对数据进行排序

2 个答案: