如何使用更新并选择表格相同的表格? MySQL的

时间:2015-06-14 15:13:17

标签: mysql sql database

我有这张桌子:

`id`      `activity_time`
 1    0000-00-00 00:00:00
 2    2015-06-1 12:12:12
 3    0000-00-00 00:00:00
 4    0000-00-00 00:00:00
 5    2015-06-2 13:13:13

我想用日期“0000-00-00 00:00:00”更新每一行,并将其设置为第一个下一个非“0000-00-00 00:00:00”行。

所以ID#1将设置为2015-06-1 12:12:12

和#3,#4将设置为2015-06-2 13:13:13

我正在尝试运行此查询:

UPDATE 
      table1
      SET activity_time =
          (
             SELECT activity_time FROM table1 as t2
             where
             t2.activity_time != '0000-00-00 00:00:00' 
             AND
             t2.id > table1.id
             ORDER BY Id ASC
             limit 1
          )
      WHERE activity_time = '0000-00-00 00:00:00'

但是我犯了这个错误:

You can't specify target table 'table1' for update in FROM clause.

1 个答案:

答案 0 :(得分:2)

在MySQL中,您可以使用join

UPDATE table1 t1 JOIN
       (SELECT t1.*,
               (SELECT t1b.activity_time
                FROM table1 t1b
                WHERE t1b.activity_time <> '0000-00-00 00:00:00' AND
                      t1b.id > t1.id
                ORDER BY t1b.id ASC
                LIMIT 1
               ) as next_activity_time
        FROM table1 t1a
        WHERE t1a.activity_time <> '0000-00-00 00:00:00'
      ) tnxt
      ON tnxt.id = t1.id
      SET t1.activity_time = tnxt.next_activity_time
      WHERE t1.activity_time = '0000-00-00 00:00:00';

基本思路是将您的查询重写为SELECT以获取所需的值。然后join返回查询以获取更新信息。

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