所以我在过去几周一直在使用php，我对此非常陌生。我在MySQL中创建了一个数据库，并使用php通过网页处理它。在将数据输入数据库中的一个表时，我已经使下面的代码完美地运行了：
Allows user to create a new entry in the database
*/
// creates the new record form
// since this form is used multiple times in this file, I have made it a function that is easily reusable
function renderForm($customer, $contactPerson, $description, $manufacturer, $serialNumber, $category, $status, $start, $end, $delivered, $quotationReference, $amount, $customerAddr, $invoice, $remarks, $error)
{
?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
<head>
<meta charset="UTF-8">
<title>New Entry Form</title>
<link rel="stylesheet" type="text/css" href="css/newstyle.css"
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script>
<script>
$(document).ready(function() {
$("#datepicker").datepicker();
});
</script>
</head>
<body>
<?php
// if there are any errors, display them
if ($error != '')
{
echo '<div style="padding:4px; border:1px solid white; color:white;">'.$error.'</div>';
}
?>
<span href="#" class="button" id="toggle-login">New Entry</span>
<div id="login">
<div id="triangle"></div>
<h1>Add Details</h1>
<form action="" method="POST">
<input type="text" placeholder="Customer*" name="customer" value="<?php echo $customer; ?>"/>
<input type="text" placeholder="Customer Address" name="customerAddr" value="<?php echo $customerAddr; ?>"/>
<input type="text" placeholder="Contact Person*" name="contactPerson" value="<?php echo $contactPerson; ?>"/>
<input type="text" placeholder="Description*" name="description" value="<?php echo $description; ?>"/>
<input type="text" placeholder="Manufacturer*" name="manufacturer" value="<?php echo $manufacturer; ?>"/>
<input type="text" placeholder="Serial Number" name="serialNumber" value="<?php echo $serialNumber; ?>"/>
<input type="text" placeholder="Category" name="category" value="<?php echo $category; ?>"/>
<input type="text" placeholder="Status*" name="status" value="<?php echo $status; ?>"/>
<input placeholder="Start Date" class="textbox-n" type="text" onfocus="(this.type='date')" id="start" name="start" value="<?php echo $start; ?>">
<input placeholder="End Date" class="textbox-n" type="text" onfocus="(this.type='date')" id="end" name="end" value="<?php echo $end; ?>">
<input placeholder="Delivered Date" class="textbox-n" type="text" onfocus="(this.type='date')" id="delivered" name="delivered" value="<?php echo $delivered; ?>">
<!--<input type="date" placeholder="Start Date" />
<input type="date" placeholder="End Date" />
<input type="date" placeholder="Delivered Date" />-->
<input type="text" placeholder="Quotation Reference" name="quotationReference" value="<?php echo $quotationReference; ?>"/>
<input type="text" placeholder="Amount" name="amount" value="<?php echo $amount; ?>"/>
<input type="text" placeholder="Invoice" name="invoice" value="<?php echo $invoice; ?>"/>
<input type="textarea" rows=4 cols=20 placeholder="Remarks" name="remarks" value="<?php echo $remarks; ?>"/>
<!--<input type="submit" value="Add Entry" />-->
<input type="submit" name="submit" value="Submit">
</form>
</div>
</form>
</body>
</html>
<?php
}
// connect to the database
include('connect-db.php');
// check if the form has been submitted. If it has, start to process the form and save it to the database
if (isset($_POST['submit']))
{
// get form data, making sure it is valid
$customer = mysqli_real_escape_string($connection, htmlspecialchars($_POST['customer']));
$contactPerson = mysqli_real_escape_string($connection, htmlspecialchars($_POST['contactPerson']));
$description = mysqli_real_escape_string($connection, htmlspecialchars($_POST['description']));
$manufacturer = mysqli_real_escape_string($connection, htmlspecialchars($_POST['manufacturer']));
$serialNumber = mysqli_real_escape_string( $connection, htmlspecialchars($_POST['serialNumber']));
$category = mysqli_real_escape_string( $connection, htmlspecialchars($_POST['category']));
$status = mysqli_real_escape_string( $connection, htmlspecialchars($_POST['status']));
$end = mysqli_real_escape_string( $connection, htmlspecialchars($_POST['end']));
$delivered = mysqli_real_escape_string( $connection, htmlspecialchars($_POST['delivered']));
$start = mysqli_real_escape_string( $connection, htmlspecialchars($_POST['start']));
$quotationReference = mysqli_real_escape_string($connection, htmlspecialchars($_POST['quotationReference']));
$amount = mysqli_real_escape_string($connection, htmlspecialchars($_POST['amount']));
$customerAddr = mysqli_real_escape_string($connection, htmlspecialchars($_POST['customerAddr']));
$invoice = mysqli_real_escape_string($connection, htmlspecialchars($_POST['invoice']));
$remarks = mysqli_real_escape_string($connection, htmlspecialchars($_POST['remarks']));
// check to make sure both fields are entered
if ($customer == '' || $contactPerson == '' || $description == '' || $manufacturer == '' || $status == '')
{
// generate error message
$error = 'ERROR: Please fill in all required fields!';
// if either field is blank, display the form again
renderForm($customer, $contactPerson, $description, $manufacturer, $serialNumber, $category, $status, $start, $end, $delivered, $quotationReference, $amount, $customerAddr, $invoice, $remarks, $error);
}
else
{
$q= "INSERT INTO brdatabase (customer, contactPerson , description, manufacturer , serialNumber, category , status, start, end , delivered , quotationReference, amount , customerAddr, invoice, remarks) VALUES ('$customer', '$contactPerson', '$description', '$manufacturer', '$serialNumber', '$category', '$status', '$start', '$end', '$delivered', '$quotationReference', '$amount', '$customerAddr', '$invoice', '$remarks') ";
if(mysqli_query($connection, $q))
{
// once saved, redirect back to the view page
header("Location: index.php");
}
else
{
echo "error : data cannot be submitted";
renderForm('','','','','','','','','','','','','','','','','','');
}
}
}
else
// if the form hasn't been submitted, display the form
{
renderForm('','','','','','','','','','','','','','','','','','');
}
?>
虽然这段代码完美无缺， 以下代码基于上述代码，似乎给了我一个我不知道如何处理的错误。
<?php
/*
NEWCOMP.PHP
Allows user to create a new entry in the database
*/
// creates the new record form
// since this form is used multiple times in this file, I have made it a function that is easily reusable
function renderForm($component, $manufacturer, $vendor, $cost)
{
?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
<head>
<meta charset="UTF-8">
<title>New Entry Form</title>
<link rel="stylesheet" type="text/css" href="css/newstyle.css"
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script>
<!--
<script>
$(document).ready(function() {
$("#datepicker").datepicker();
});
</script>
</head>
-->
<body>
<?php
// if there are any errors, display them
if ($error != '')
{
echo '<div style="padding:4px; border:1px solid white; color:white;">'.$error.'</div>';
}
?>
<span href="#" class="button" id="toggle-login">New Entry</span>
<div id="login">
<div id="triangle"></div>
<h1>Add Details</h1>
<form action="" method="POST">
<input type="text" placeholder="Component*" name="component" value="<?php echo $component; ?>"/>
<input type="text" placeholder="Manufacturer*" name="manufacturer" value="<?php echo $manufacturer; ?>"/>
<input type="text" placeholder="Vendor*" name="vendor" value="<?php echo $vendor; ?>"/>
<input type="text" placeholder="Cost*" name="cost" value="<?php echo $cost; ?>"/>
<input type="submit" name="submit" value="Submit">
</form>
</div>
</form>
</body>
</html>
<?php
}
// connect to the database
include('connect-db.php');
// check if the form has been submitted. If it has, start to process the form and save it to the database
if (isset($_POST['submit']))
{
// get form data, making sure it is valid
$component = mysqli_real_escape_string($connection, htmlspecialchars($_POST['component']));
$manufacturer = mysqli_real_escape_string($connection, htmlspecialchars($_POST['manufacturer']));
$vendor = mysqli_real_escape_string($connection, htmlspecialchars($_POST['vendor']));
$cost = mysqli_real_escape_string($connection, htmlspecialchars($_POST['cost']));
// check to make sure both fields are entered
if ($component == '' || $manufacturer == '' || $vendor == '' || $cost == '')
{
// generate error message
$error = 'ERROR: Please fill in all required fields!';
// if either field is blank, display the form again
renderForm($component, $manufacturer, $vendor, $cost);
}
else
{
$q= "INSERT INTO compdatabase (component, manufacturer, vendor, cost) VALUES ('$component', '$manufacturer', '$vendor', '$cost') ";
if(mysqli_query($connection, $q))
{
// once saved, redirect back to the view page
header("Location: pricelist.php");
}
else
{
echo "error : data cannot be submitted";
renderForm('','','','');
}
}
}
else
// if the form hasn't been submitted, display the form
{
renderForm('','','','');
}
?>
我收到错误＆＃34;第34行＆＃34;未定义的可变量其中包含带有（$ error！=＆＃39;＆＃39;）条件的if语句。我不清楚如何用$ error解决这个问题。 我真的很感激任何建议和帮助。我仍然是PHP的新手，希望能够解决所有这些疑虑
答案 0 :(得分：0)
<?php
/*
NEWCOMP.PHP
Allows user to create a new entry in the database
*/
// creates the new record form
// since this form is used multiple times in this file, I have made it a function that is easily reusable
function renderForm($component, $manufacturer, $vendor, $cost)
{
?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
<head>
<meta charset="UTF-8">
<title>New Entry Form</title>
<link rel="stylesheet" type="text/css" href="css/newstyle.css"
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script>
<!--
<script>
$(document).ready(function() {
$("#datepicker").datepicker();
});
</script>
</head>
-->
<body>
<span href="#" class="button" id="toggle-login">New Entry</span>
<div id="login">
<div id="triangle"></div>
<h1>Add Details</h1>
<form action="" method="POST">
<input type="text" placeholder="Component*" name="component" value="<?php echo $component; ?>"/>
<input type="text" placeholder="Manufacturer*" name="manufacturer" value="<?php echo $manufacturer; ?>"/>
<input type="text" placeholder="Vendor*" name="vendor" value="<?php echo $vendor; ?>"/>
<input type="text" placeholder="Cost*" name="cost" value="<?php echo $cost; ?>"/>
<input type="submit" name="submit" value="Submit">
</form>
</div>
</form>
</body>
</html>
<?php
}
// connect to the database
include('connect-db.php');
// check if the form has been submitted. If it has, start to process the form and save it to the database
if (isset($_POST['submit']))
{
// get form data, making sure it is valid
$component = mysqli_real_escape_string($connection, htmlspecialchars($_POST['component']));
$manufacturer = mysqli_real_escape_string($connection, htmlspecialchars($_POST['manufacturer']));
$vendor = mysqli_real_escape_string($connection, htmlspecialchars($_POST['vendor']));
$cost = mysqli_real_escape_string($connection, htmlspecialchars($_POST['cost']));
$error = '';
// check to make sure both fields are entered
if ($component == '' || $manufacturer == '' || $vendor == '' || $cost == '')
{
// generate error message
$error = 'ERROR: Please fill in all required fields!';
// if either field is blank, display the form again
renderForm($component, $manufacturer, $vendor, $cost);
}
else
{
$q= "INSERT INTO compdatabase (component, manufacturer, vendor, cost) VALUES ('$component', '$manufacturer', '$vendor', '$cost') ";
if(mysqli_query($connection, $q))
{
// once saved, redirect back to the view page
header("Location: pricelist.php");
}
else
{
echo "error : data cannot be submitted";
renderForm('','','','');
}
}
}
else
// if the form hasn't been submitted, display the form
{
renderForm('','','','');
}
?>
<?php
// if there are any errors, display them
if ($error != '')
{
echo '<div style="padding:4px; border:1px solid white; color:white;">'.$error.'</div>';
}
?>
答案 1 :(得分：0)
好的，所以在修修补补之后，我意识到这个错误非常愚蠢。我必须确保在使用它之前已经完成了对$ error的赋值，并且在之前的代码中它还没有完成。我只是在第34行使用$ error而不检查它是否先前已分配。
我的错误是在我的行
function renderForm($component, $manufacturer, $vendor, $cost)
我所要做的就是分配错误并使其成为
function renderForm($component, $manufacturer, $vendor, $cost, $error)
这也需要编辑，无论我通过添加额外属性$ error使用他的功能。我希望遇到这个问题的任何人都知道他们现在应该检查什么。