Question

我有一张名为＆＃34的订单;订单＆＃34;在SQL数据库中：

if ( !empty($_POST)) {
        $name = $_POST['name'];
        $valid = true;


        if ($valid) {
            $pdo = Database::connect();
            $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
            $sql = "INSERT INTO orders (name,date) values(?,CURDATE())";
            $q = $pdo->prepare($sql);
            $q->execute(array($name));
            Database::disconnect();
        }
}

＆＃34; id＆＃34;设置为AUTO_INCREMENT和＆＃34;日期＆＃34;当我通过我的PHP表单插入数据时创建：

id  date   name  orderID
========================
1   1502   John    15021
2   1502   Jane    15022

我希望＆＃34; orderID＆＃34;的价值是从值＆＃34; id＆＃34;自动创建的。和＆＃34;日期＆＃34;：

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Answer 1

由于事实，id是AUTO_INCREMENT，您无法接受此值。但它很简单。向表中添加AFTER INSERT触发器，然后让它更新orderID列。

这是AFTER UPDATE触发器的快速示例。

CREATE TRIGGER yourTrigger
AFTER INSERT
   ON yourTable FOR EACH ROW

BEGIN
    UPDATE yourTable
    SET orderid = CAST(date as char(4)) + CAST(id as char(1))
    WHERE ID = NEW.id

END;

Answer 2

试

    if ($valid) {
        $pdo = Database::connect();
        $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
        $sql = "INSERT INTO orders (name,date) values(?,CURDATE())";
        $q = $pdo->prepare($sql);
        $q->execute(array($name));

        $q = $pdo->prepare( '
             update orders
             set orderId = id
             where id = SELECT LAST_INSERT_ID()'
        );
        $q->execute();          

        Database::disconnect();
    }

现在应该工作

Answer 3

SET @last_id_in_table1 = LAST_INSERT_ID();
INSERT INTO orders (name,date,orderID) values(?,CURDATE(),@last_id_in_table1 )

Answer 4

不要在数据库中创建另一个列来保存此值，它只是重复的数据，只会占用不必要的空间。

检索数据时，可以使用CONCAT(id, date) AS orderid来获取连接值。

例如，获取John的所有orderid：

SELECT CONCAT(id,date) AS orderid from `orders` WHERE `name`="John"

如何在SQL中的同一个表中从其他两个值创建值？

4 个答案: